Question
Which inequality contains both solutions of $x=\frac{1}{2}+\frac{3}{x} ?$A. $-1 < x < 3$B. $-2 < x \leq 2$C. $-2 \leq x < 0$D. $-3 \leq x \leq-1$
Step 1
Step 1: First, we rewrite the equation with a common denominator of $x$: \[x = \frac{1}{2} + \frac{3}{x} \Rightarrow x = \frac{x + 6}{2x}\] Show more…
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Which pair of inequalities is equivalent to $0<x \leq 3 ?$ $$ \begin{array}{ll}{\text { (a) } x>0 \text { and } x \geq 3} & {\text { (b) } x<0 \text { and } x \geq 3} \\ {\text { (c) } x>0 \text { and } x \leq 3} & {\text { (d) } x<0 \text { and } x \leq 3}\end{array} $$
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Which pair of inequalities is equivalent to $0<x \leq 3 ?$ (a) $x>0$ and $x \geq 3 \quad$ (b) $x<0$ and $x \geq 3$ (c) $x>0$ and $x \leq 3 \quad$ (d) $x<0$ and $x \leq 3$
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