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SA
Numerade Educator

# Which measure of central tendency best represents the data? Justify your selection and then find the measure of central tendency.(GRAPH NOT COPY)

### Answer

#### Topics

Rational Functions

### Discussion

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##### Top Algebra Educators    ##### Kristen K.

University of Michigan - Ann Arbor

### Video Transcript

All right. So we have a comparison here of the average solar hours for each state, and we want a first of all fine, the mean So we want to know what are the average solar hours for all of the states to find the mean, We're gonna find this some divided by our number, and that would be the number of categories. So we add up all of our hours. Here we get 535 and there are five different states in our data set. So where are mean would be 107. Let's look for the media. Next, the median value is the value that is in the middle, so the little value is found when we put these in order, all of our data order from least the greatest be 65.5, 79.4 83.1, 88.6 and 218.4. The one that's in the middle is 83.1. So that's our immediate. We don't have to worry about the mode because there is not a moat for this, Data said. There's not a number that appears more than others or states that have the same number of silver hours, I should say now which one will be a better measure of central tendency? Would it be the medium, which is 83.1, or could it be the mean of 107? Well, in this case, we have what's called an outlier if you look at California. California, of course, has a lot more solar hours than any other state listed here is on the West Coast. Um, compared to these other states in this is average solar hours for I don't know what what time period. So 218 is what we would call more of an outlier. And because the median does a better job of finding this central tendency when there's a wider range of numbers or an outlier, we would say the median is our best bet, and that would be the better measures of central tendency

#### Topics

Rational Functions

##### Top Algebra Educators    ##### Kristen K.

University of Michigan - Ann Arbor