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# Which measure of central tendency best represents the data? Justify your selection and then find the measure of central tendency.(GRAPH NOT COPY)

## Mean; there are no extreme values. 788.8

#### Topics

Rational Functions

### Discussion

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##### Kristen K.

University of Michigan - Ann Arbor

##### Michael J.

Idaho State University

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### Video Transcript

a baker wants to know more about the average number of cake sold. Um, only So we have the type of cake. So, um, last month, how many of each type? Now, if we want to find the mean of this data set, we know we're gonna add up all of the cake. So last month, that gives us 2628. That's our some divided by the number of types. So the sum is 2628 and we know we have five different types of cake that's going to give us a mean of 525.6 around to the nearest tense place. The median here means that we're gonna have to look for the middle value. The middle value is only found when we have our numbers listed from least the greatest. So we're gonna have to go back and do that. See? So, starting with the smallest number, I'm just checking it off as we go. Then we'll have 501 which was strawberry. 512 543 576. So the median number of cakes here would be 512 which is the butterscotch. Okay, we don't have to worry about mode because there is not a number that occurs the most. So there's no mode in this situation. Which measure of central tendency works better? Would it be the mean or the median in this situation? I think you could make a strong case for the mean In terms of that baker. Knowing 525 is the number of cakes you know altogether, the mean takes into account all data points. So that's one reason why the mean is really good to use. However, if you look at the median, the good thing about it is that we know that butterscotch was the one that was in the middle. So really depends on exactly how you're going to use the information. Um, I would say, probably in this case, the better measure of central tendency would be the mean

#### Topics

Rational Functions

##### Kristen K.

University of Michigan - Ann Arbor

##### Michael J.

Idaho State University