which-of-the-following-circuits-would-have-an-equivalent-resistance-equal-to-that-of-the-circuit-dep

Question

Which of the following circuits would have an equivalent resistance equal to that of the circuit depicted above?
a. IMAGE IS NOT AVAILABLE TO COPY
b. IMAGE IS NOT AVAILABLE TO COPY
c. IMAGE IS NOT AVAILABLE TO COPY
d. IMAGE IS NOT AVAILABLE TO COPY

Linda Winkler · Accepted Answer

circuits is the many ways and arrangements that you can take resistors and show them. Um And I&#x27;ll show you some of the things that you can do with a simple arrangement of resistors in series and parallel that might confuse some people. Um But certainly the order in which the resistors are drawn can be rearranged and so that&#x27;s something to get used to. So here we have um two Ohm resistor in series with her battery and a couple of resistors in parallel, followed by another set of resistors in parallel. And it is important to realize that the order of those does not matter at all. Um So you can for example take that too series resistor and move it In between the other two and moving any group of resistors into a different position in series with that battery does not change either the main current that flows through the battery. And of course it doesn&#x27;t change the individual currents that flow through those uh individual resisters. So there&#x27;s there&#x27;s four individual resisters. Um No change. Yeah. So important conclusion, the water of the resistors does not matter. And likewise, uh It&#x27;s important to realize that you can reverse the order of the parallel resistors as well. Um And again there will be no change. So for example you can take the last set of parallel resistors and you can just flip the top and the bottom. It&#x27;s a three OEMs. So no difference there. And you might ask why can you do that? Um Electrically speaking, you still have the same potential difference across um Those two resistors no change two delta v. Um So the important thing to realize about series series means um same current through all the components. And so it should not matter what order to arrange them in. Whereas parallel means the same potential difference between the top and the bottom of resistors connected this way. Uh And so it shouldn&#x27;t matter, you know which, how you&#x27;ve drawn them, we&#x27;ll put it that way. Um There&#x27;s one last thing you can do to this circuit. You can make any of those resistors a little bit more complicated. For example, you could take the two ohm resistor uh and turn it into a series. You can do this to any of them, but you can take it and turn it into a on one own plus a one ohm. You could even do one half Plus one of all. And there will again be no change to the circuit if you take any of those resistors and swap them out with an equivalent resistance. Um And as one last example, you can take that to OEMs and even make it a more complicated parallel situation, like a three homes In parallel with six homes. Okay, so lots of ways to rearrange resistors. I&#x27;m not going to show too many different ways to draw them. One of the things teachers like to do to confuse students is instead of drawing a square uh huh Or rectangular type situation with two resistors in parallel, um say the 1.5 and the three homes is to just make the wires look a little bit different. Um Put one of those resistors at a diagonal to the other and that should not matter either. A wire is a wire, regardless of how it&#x27;s bent. Um The important thing is how the two components are connected, hum. Mhm.

Ze-Han Lee · Answer

All right. So in this problem Ah, we have this circuit. So in part A, we want to ah, determine the current through each resistor. So we already know the current through through this wise ah, 0.5 years, right? And we look at the three branches. So this one is also 60 homes. And the combined resistance of this tour is also 60 on this is 60. So, uh, we&#x27;re easily we can see that the current through each branch, his 0.5 n peers there&#x27;s a 0.5 AM Piers. This is a 0.5 years. Okay, So part, eh? And this one, it&#x27;s 10.5 m peers according to a problem. So the total current through the membrane tch is ah, 25 plus 0.5 plus 0.5. Okay, which is 1.5 years. And for B, we want to know the potential difference across the resistor. So we know that the current in the mem branches that 1.5 m peers and this is the tunnels, right? So the potential difference across this one So that&#x27;s it is our one. Okay, So v one, it called 1.5 and peers times are what? Which is 15 hopes 15 waltz, and they&#x27;re supposed this are too. So V two equal 20.5. I&#x27;m piers times 60 are too. They&#x27;re called 30 votes. And as you can see that to these are two is in parallel with this one, Ray. So this was also 30 or 30. 30 volts? Yeah, and the current in the second branch is also 0.5 appears. So the body across this 20 homes is Ah ah, 20 homes, times 0.5 years, which is turn warts. Okay. And the devoted across this one 40 arms is fourty arms. Times 0.5 years equal 20 months. All right, so yeah, and ah, for Parsi. What is the equivalent? Resistance of the of the circuit says that we can see that these two worrying serious Ray. So this, too. We&#x27;ll combine as, ah, 60 homes resistant into this one. This one and this one. They&#x27;re in peril, so we can list Equation went over our Let&#x27;s see, this is our, um because we have the full resistance together. Right? So let&#x27;s say this are full equal. One over 60 plus well over 60 plus one over 60 right? This is the parent estimation rule so I can see that our four equal 20 homes and our boys in part, always are one ray. So the total resistance Pequot are one plus are full, equal 30 bones. All right.

Luis Rios · Answer

So here we have three circuits and our goal is to find that equivalent resistance if it exists for each one. So for part A on the left side, that&#x27;s the circuit we have, then the middle line we can eliminate because there&#x27;s no resistance in there. So it simplifies to the circuit on the right. And now we notice that the resisters on the left and right side are in parallel with each other, so they&#x27;re in parallel. Then, for each weaken, say one over. Alright, equivalent is equal to one over R one plus one over R one. So then we Adam up and then take the reciprocal to get our equivalent we have are equivalent is equal to are 1/2. So then the circuit simplifies to something easier. Now we just have to your sisters each with on 1/2 a little too. And, of course, these are now in Syria with each other. So then, if they&#x27;re in serious, we just Adam up. So it&#x27;s 1/2 this 1/2. So are equivalent resistance. It&#x27;s just are one, not for part B. There&#x27;s no line in the middle now, and so we see that all the resisters on the left side are in series of each other and all the resisters on the right are in a serious with each other as well. It&#x27;s up there in Siris. We just Adam up. So our workers are one. You get to our one for the left and then to on one to the right, and these are in parallel to each other. Then we can save one. Over are equivalent is equal to one over to our one, this one over to arm one. So the Adam up take the reciprocal we have our equivalent equals R one. Now for part C. This is a really complicated circuit. If you notice are one on the left side, the current flowing through here can either go to the middle one, but the bottom one and there&#x27;s no way of knowing. So we can&#x27;t say the top resistor. This one isn&#x27;t syriza this one. We can&#x27;t stand the right that this top Ryan resistor isn&#x27;t serious with this one. And these are not in parallel with each other either. Since you can&#x27;t Adam up in Siris or in parallel, then there&#x27;s no equivalent resistance are just none

Manish Haldankar · Answer

No. I shown in the diagram. Well, mation that Let&#x27;s take it a step one. Now let the effective resistance for the circuits such as a be and D Well, I did b are effective. So therefore in these three circuits are effective is equal to are bless our batter to our because all the red distances are no same value And if you observe in the circuits tour distances are in parallel because they&#x27;re connected across and this paddle combination is in serious with one register. So if we saw this further R plus now value of the Do Ra distances is calculated as my application off due to the senses Do you wanted by addition off to So it is going to be our plus our square a point to our we saw this year. Therefore, are you thick? Do is equal to r plus r by two and that is going to be too are less are born to and this would be three times are born to Bill mentioned the unit s o. So so get a B and d are effective is off value with his three are a point to now that&#x27;s more head And so for a step, too. Now, in this particular step for so good, see, let the effective resistance be RS. Now we&#x27;ll try to find out the value of artists as since the same current is flowing through all the red distances they are connected in cities. That&#x27;s reason the addition off three will be terrific. You&#x27;re a distance summation. The resisters, as three are no. So you write the conclusion here. So considering supply off the battery remains the same, it will supply the same current in the circuits such as Second A. B. Andy, and this is going to be the answer for the question, which has been last.

Sheh Lit Chang · Answer

this question. We are given this circuit. So there are four things, therefore, parts in this question. So first we need to find equivalent resistance. Find potential. Then we need to find potential difference across each resistor. The indicated currents, I want to I five. And the power delivered to each with is the Okay. So to do part A care to do quite a you first need to recognize that the six home and then I own they are parallel to each other. Okay, so I&#x27;m just going to redraw the circuit. Okay? Six or he moves. Six own, 2.4, uh, six on. Okay, So, um, the 1/6 plus one of the nine in verse, you calculate you get 3.6 old. So this is 3.6. Then you notice that, uh, this can be simplified into. Ah, a six owns six, owns six owns and six homes. Yeah, so from here, we can actually find the total resistance now, so the equivalent resistance is equal to six classics class. The parallel part, Okay. And then you calculate you get 15 homes. Okay, So this is the answer for part a, then parts be. We need to find, uh, the potential difference across each resistor. So just to redraw the circuit again, Okay. E f Yeah. Okay. So, um, so this is how I&#x27;m going to do the write down the answers. Okay, So, um okay, Based on what we know just now, the equivalent resistance is 15 homes. Okay, so the current in the battery is equal to one MPs. Okay, so this is just the over our okay. 15 divide by 15. Mhm, then Delta V a c. Okay. It&#x27;s just, uh, high times are so it&#x27;s six votes. Six owns times one NPR. So it&#x27;s 6.0 world, and then the entire V b d. Okay. This&#x27;ll is also equal to six votes. Um Okay. So, uh, so just now we saw that, uh, we can reduce a circuit into like this right? Design party. Okay, so this is six votes. Um, the six words this part will be tributes and tributes. Okay, So Delta v. C d. It is going to be three votes. Okay. And then, uh, Delta v ce. Okay, so this is one MPR. This is going to be 0.5 NPR and 0.5 NPR. Okay, so the VI CE will be 2.4 own times 0.5. So this is 1.2 words, okay? And then the HIV CD, because Delta V, uh, f d is going to be 1.8 words. Okay. Yeah. So So that&#x27;s all for part B. Hey, you know the answers. Okay, then in proceed, we want to find the currents. Okay, So just usual. It&#x27;s like it again. Hey. Six own six own six, owns six arms, the 0.4 rooms. Ni owns 13 words in the currents. I won I to I tree I for Hi. Fine. Okay, So just now, I When I did part B, I also kind of mentioned some of the currents, so I want is going to be one NPR I to is 0.5 MPs. Okay, I tree is 0.5 MPs. I fall. Um, he&#x27;s going to be Ah, 0.3 MPs and then I five is going to be 0.2 MPs. Okay, so, um, so this is just so if you go through the reasoning, this is just parallel. Arrangement off. Six owns 86 only six on. Okay, once we reduce based on what we did in previous parts, Okay. Here. Eye for an eye. Five. What happens is that you know that I fall Plus, I five equals to zero point five NPR. We also know that six times I fall equals to nine times I find because they are parallel. Okay, so when you solve, I follow the 0.3 and I 50.2. Right. So when you put them, you get 1.8 equals to 1.8. Okay, so this is the answer for Patsy. Okay, then body. Okay. Finding the power delivered to each resistor. Okay, so, um, this rejoined the circuit again. A 15 year olds six own, 2.4 own six. Only six old six owns NYT owns. Okay, So just now we know that the current this is one NPR, this is 0.5 NPR Things is also going to be one NPR. Ah, your point to NPR. Your country, NPR. You&#x27;re 25 NPR. Okay, so we&#x27;re going to, uh, going to labor some of the resistance. So this is one to three. Uh, I six. Okay, So k p one is, uh, I square are I&#x27;m going to use I square are throughout. So this is this using this formula, I get 6.0. What p one or p two is your 0.5 square time? Six. So I get 1.5. What? Petri. It&#x27;s one square time. Six 6.0. What p four This 0.5 square times 2.4. So this is your 0.6. What? An MP five is equal to your country. Square times six this is 0.54 What in the n. P. Six eyes, 0.2 square times nine The 0.36 What? Uh huh. So here are the answers for this question. Right? And that&#x27;s all for this question.

Jilin Wang · Answer

Okay. We have a circus here. Will assume that the current across the battery is I. The current Go through. Our one is going down quickly. I want the current goes through our three weekly eye too. So the current goes through our two According to junction room on B, I&#x27;m ice. I want the current goes to our five. It&#x27;s going to I minus. Sorry, There&#x27;s I, Linus. I want I mean, say one. And here the current goes dry for is I want mine. Okay. So whose are these assumptions? We can start to write the loop rules. Okay, so for this left group here looking right, I left you so fourteen minus. I won. I&#x27;m Swan. Just I want minus two. I&#x27;m swine. One mine inside you, which will give us zero. And we know three. I want it with you two. No, we know that three. I won minus two eye too. Twenty four. The tough new here. Okay, half. Thank you, two. I will. I&#x27;m going to say one plus I too. I&#x27;m sworn thus I want with zero which will give us Let Teo I best three. I won. Yes, I too. Which is and the party circuit here. Okay. Half negative. I want I&#x27;m minus. I want to. That&#x27;s one thus, too. I want mints. I do minus I two time Swan equal zero, Which will give us. I might. US native I plus three. Oh, one minus four. Eye too. Coaches. So we have three questions. Really knew invariable. So I guess so. I you could tell him which is the current Go through the back on one. I got you sic semper, which is a current goes to o R one two it wanted to enter, which is a turn to go through Arthur and Chris Spelling Lee. I minus I want what you ate. No, it could you four. I want my side to you before too. And I guess I won that side to just six. So that&#x27;s all the current with So so or question be the equivalent resistance. It&#x27;s just simply the total The Yemen divided by the total current, which is I porting. You&#x27;ve ever ten is about one point four

Problem

Escape velocity is defined as the minimum speed a…

Problem 22 Easy Difficulty

Which of the following circuits would have an equivalent resistance equal to that of the circuit depicted above?
a. IMAGE IS NOT AVAILABLE TO COPY
b. IMAGE IS NOT AVAILABLE TO COPY
c. IMAGE IS NOT AVAILABLE TO COPY
d. IMAGE IS NOT AVAILABLE TO COPY

Answer

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