(NH_{4})_{2}\mathrm{SO}_{4}.6H_{2}O$, can react with $\mathrm{KMnO}_{4}$ in acidic medium. The reaction is as follows:
\[\mathrm{FeSO}_{4}.(NH_{4})_{2}\mathrm{SO}_{4}.6H_{2}O + \mathrm{KMnO}_{4} + H_{2}SO_{4} \rightarrow K_{2}SO_{4} + MnSO_{4} + Fe_{2}(SO_{4})_{3}
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