03:04
Part a says, suppose that an alkaline battery was manufactured using cadmium metal rather than zinc.
03:11
What effect would this have on the cell emf? all right, so we're thinking about using cadmium instead of zinc.
03:26
All right, so in zinc, the reaction is zn2 plus plus two electrons goes to zn, and that has an e knot equal to negative 0 .76 volts.
03:46
Cadmium is also a 2 plus charge, so it would be plus 2 electrons, and it has an e knot of cd, i'm going to, sorry, to cd, and it has an e knot equal to negative 0 .40 volts.
04:06
So this would be the anode.
04:11
And in the problem, it says that this is the anode.
04:18
Okay, so this is where, because it's the anode, remember, the anode is where the oxidation reaction is occurring.
04:23
And so for oxidation, since these are reduction potentials, for oxidation, we want a bigger negative number.
04:35
So the bigger the negative number, the more likely it is to be the oxidation reaction.
04:41
And cadmium is a smaller negative number...