which-of-the-following-is-true-regarding-conservative-forces-select-two-answers-a-the-work-done-by-c

Question

Which of the following is true regarding conservative forces? Select
two answers.
(A) The work done by conservative forces is path dependent.
(B) The work done by conservative forces is path independent.
(C) Gravity is a conservative force.
(D) Friction is a conservative force.

Salamat Ali · Accepted Answer

worked on by there. Conservative forces is in the independent off apart, so it&#x27;s independent off. And, uh, gravity is the force, which is a conservative force, so B and C are the right options.

Averell Hause · Answer

So here the answer is C Essentially, we have gravitational force and this is for a few reasons. First, um, gravitational force is a conservative force. First of all is pathway independent. Uh, we also we can also say that it does not dissipate a mechanical energy, and this is essentially, um, kind of essentially like friction in the sense of if friction. If we were to say, friction eyes a non conservative force because it actually we have mechanical energy worthy or kinetic energy energy in the form of movement. And it is, um, creating some sort of, uh, frictional force acting in the opposite direction. Now we can say, of course, air assistance, eyes essentially just friction. And, ah, conviction. Eyes not a force, but rather a method of heat transfer. And so, of course, that is not a a conservative force. So again, final answer See, gravitational force is the only conservative force that is thean of the solution. Thank you for watching

Averell Hause · Answer

So here we have the, uh, movement on a plane with friction. We can say that this plane can be horizontal. It can be on an incline regardless. Ah, we have represented with three statements we have acceleration is a function of applied force only. And in the case with the incline, we can actually just have gravitational force and the force normal. Here we can say that the force of friction is not enough to keep it stationary. And so here, in the absence of an applied force, we can potentially have Ah, the mass traveling down the incline due to the gravitational force, not an applied for us. So we can eliminate a statement one and we can say that more force is needed to accelerate a stationary object. Uh then an identical moving object. Now, this is true with force of friction. We know that the force of friction will be equal to the coefficient of friction multiplied by the normal force. No, In the case of the horizontal plane, we have the coefficient of friction times, the gravitational force and in the case of the incline, we have the coefficient of friction times, MGI and this would be signed brother co sign of data. And so in this case, we can say that regardless, the coefficient of static friction is always greater than the coefficient of kinetic friction. Which means that here for a stationary object MAWR forces needed to overcome friction, given that the maximum static frictional force is always greater than the kinetic frictional force. And so we can say that statement to is correct. Statement three. Now we have. Then the force of friction is independent of the mass. And as you can see here, it is not independent of the massive, directly proportional to the mass. And so statement three is false. And so we can say that the answer would be option B, where only statement to is correct. That is the end of the solution. Thank you for watching

Jordan Gassaway · Answer

So if you remember, a known conservative force is one where the path between starting and the final positions ah, is relevant to the change in energy of the system. Ah, whereas a conservative force they path has taken is not relevant, we&#x27;re only care about the final or the starting in the final position. For example, gravitational potential only depends on the height. It doesn&#x27;t actually depend on what path we took to get there. Friction being a non conservative force, uh, energy will be expended at every point along this path. And so it does matter in a physical sense. We can think of that as if we have our system, um, and where putting energy and getting work out and possibly changing this potential energy of the system. The non conservative force is one where we have energy leaving the system by this queue out here that we can&#x27;t recover, so it&#x27;s non usable, doesn&#x27;t go into the work part of are changing energy. And so these are gonna be forces like sound light friction. Ah, heat dissipation, energy that&#x27;s typically dissipated into the environment and isn&#x27;t able to be recovered

Abhishek Jana · Answer

so we can take an example off uniform circular motion. So let&#x27;s let&#x27;s assume that an object is moving in the uniform circular motion with, ah, constant speed. So even if the object is moving in a circular motion with the constant speed, the velocity is changing every moment because the velocity is the direction, Um, which makes a tangent at the point of the circle. So at each point, the attendant is different. So that&#x27;s why the direction of the velocity exchanging. Although the magnitude remains constant, so the velocity is constant. In that case, option is true. No, the object is, as we mentioned, that changing the object is changing its direction. So that means auction bees true as well. But we&#x27;ll come back to Option C because ax elation is not cereal here. So we have to see if that condition satisfies here or not. But we see that the centripetal force is the net force acting on the object, and that&#x27;s greater than zero. So that means d seems to be true also from the work energy theorem. We see that since the object is moving so we only have kind of energy here and the the kinetic energy is changing. So the change in kinetic Sorry, the kind of again it is not changing here because the velocity is constant. So that means the next change in kinetic energy and the network are both zero. So that means he&#x27;s through. So the only option that seems not true is option C where ax elation is here. So I mean, as we see here, that ax elation is nausea because the very sentimental acceleration which is acting towards the center, so the option C seems to be the answer.

Ze-Han Lee · Answer

So in this problem, uh, we have four statements. So in the 1st 8 many states that Ava objects center rations, counted it, then muster moving the straight line. So this is not right because he gave you threw a ball from the ground and see that the acceleration is constant. Which evil G but to the movement is not straight line. All right, it&#x27;s ah, it&#x27;s a projectile. So in part B in the choice B, I says even objects acceleration zero. Then the speed might must have returned. Constant constant. That s o This is right. So the choice bees, right. His choice, eh? And chose. C says that if the object of speed return constant, then the generation must be zero. This is not right. So if you look at ah ah, circular moat if you look at the second movement, so see that to the the The speed is a constant, but to the acceleration is no zero. There is a fine it. Ah, centripetal acceleration. Okay. And in part d say&#x27;s, uh if the objects of direction of the movement is changing the acceleration zero, that&#x27;s that. Is that this is right. Okay,

Problem

Based on data in the table, in what percent of c…

Problem 49 Medium Difficulty

Which of the following is true regarding conservative forces? Select
two answers.
(A) The work done by conservative forces is path dependent.
(B) The work done by conservative forces is path independent.
(C) Gravity is a conservative force.
(D) Friction is a conservative force.

Answer

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