00:01
Here we are given lower quartile, okay, to be q1, okay? and we are given upper quartile, upper quartile to be q3, okay? and we are given interquartile distance, interquartile distance to be equals to q.
00:28
Okay, we know that the formula of interquartile distance is nothing but q3 minus q1, okay? this is the formula of interquital distance now the condition which we have given is that average of q1 plus q2 plus q is given to be 40 okay this will be the average and is it it is given to be equals to 40 so from here sorry it is q 3 from here we can say that q1 plus q 3 plus q is coming out to be equals to 120.
01:05
Okay.
01:05
Now we know that q is given by q3 minus q1.
01:11
Okay.
01:12
So if we put the value of q here, what we get is q3 plus q3 minus q1, okay, equals to 120.
01:23
So from here, the value of q3 comes out to be 60...