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This question asks about which statement is true regarding a covalent bond forming.
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So let's go over the concept of a covalent bond.
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Covalent bond is defined as the shared electrons on the valent shell between two nuclei.
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So the keywords here are shared electrons on the valent shell.
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Valent shell is also known as the outermost shell.
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So let's take water as an example.
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As we all know that water is h2o, so one oxygen atom and two hydrogen atoms.
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An oxygen atom has 8 electrons in total, with 2 on the inner shell and 6 on the outermost shell, or the valent shell.
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And h has only 1 electron.
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And there is only one shell.
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So for the oxygen, we have two on the inner shell and six on the outermost shell.
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One, two, three, four, five, six.
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And as you can see that these two electrons are not paired.
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And for hydrogen, we have only one electron and the same here as well.
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So we know that for the first shell, we need to the first shell, two electrons to reach a stable state.
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And for the second shell, we need eight electrons in total to reach a stable state.
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And as you can see, now we have unstable shells on both o and h atoms...