00:01
Hello, everyone.
00:02
This is ricky, and today we're working on problem number seven.
00:06
So which of the following slightly soluble compounds has a solubility greater than what its calculated value is due to hydrolysis of an ion being present? so what this means is, so say, for example, we are looking at, we're looking at calcium fluoride.
00:34
So calcium f2.
00:38
This dissociates into calcium and to fluoride ions, very weakly.
00:45
However, fluorine plus hydronium leads to hydrofluoric acid and water.
01:04
And so this is a very weak acid, meaning it partially dissociates.
01:07
That means if we're increasing the amount of fluorine, we're going to be here, let me do this in a different color.
01:15
If we're increasing the amount of fluorine, we're going to be pushing equilibrium this way, which will further decrease this fluorine, which will slightly increase the solubility.
01:29
Let's just go through some of the other salts that were given to us and determine which ones are weak acids or their ions, the conchidate base for weak acids.
01:46
Okay.
01:49
So we have, so we have agcl, b -a -s -o -4, caf -2, which i just went through for you, h -g -2, i -g -2, and then co3, sync sulfate, and then lead -sulfate...