00:01
We want to determine what of the sequence a .n is equal to the natural log of n plus 1 over the square root of n converges or diverges.
00:09
N if it converges but it converges two.
00:11
So let's go ahead and write our limit first.
00:13
So the limit as in approach to infinity of a .n is equal to the limit as in approaches infinity of the natural log of n plus 1 over the square root event.
00:32
Now notice, if we just go ahead and evaluate this limit, well, the natural log function would have infinity on the end side.
00:44
And so the natural log of infinity goes to infinity.
00:49
And the square root of n, well, that would also go to infinity.
00:54
So this here implies we can apply lopithal rule, which i'll abbreviate as lh, which means this limit here will be equal to by lopithelial, the limit as in approaches infinity of the derivative with respect to n of a natural log of n plus 1 over the derivative with respect to n of the square root of it.
01:28
Now, this will be the limit as n approaches infinity.
01:35
So remember, to take the derivative of natural log of 1 over m, it will be 1 over m plus 1 times the derivative of the n side, which is just 1...