00:01
We want to determine whether the sequence am is equal to natural log of n to the 200 power over n converges or diverges, and if it converges, what it converges to.
00:13
Well, let's go ahead and first just see what happens as we evaluate this at infinity.
00:20
So as in the cruxed infinity, well, we know natural log of infinity and then raising something to composite power, which is still good infinity.
00:29
So we have infinity and n goes to infinity as well.
00:33
So what this tells us is we should apply local tall rule.
00:37
So let's go ahead and take the limit of this.
00:40
So the limit as an approaches infinity of am, this is going to equal to the limit as in approaches infinity.
00:51
And this is by localities.
00:54
When we take the derivative of our numerator, so we're going to need to use chain rule to do this.
01:00
So the derivative of our outside function, well, that's x to the 200 power to use power rule.
01:07
It be 200 times the natural log of n.
01:11
Now to the 199 power.
01:14
And then we have to multiply by the derivative on the inside, which is natural log of n.
01:20
So we would multiply this by one over n.
01:23
And then we divide this by what we get in the denominator, which is 1.
01:28
Well, we can leave that one over in into the denominator, and we would be left with the limit as an approach of infinity of 200 natural log of n over 199 over in.
01:48
And if we were to look at the limit as an approach's infinity of this expression here, well, it's going to be the exact same thing that we had to start.
01:59
So it's still going to be infinity over infinity, so we still need to use lopetal's rule.
02:04
So let's go ahead and apply lopatol rule one more time.
02:08
So i'll move this down here...