which-one-of-the-following-statements-is-true-concerning-the-motion-of-an-ideal-projectile-launched-

Question

Which one of the following statements is true concerning the motion of an ideal projectile launched at an angle of 45° to the horizontal?
(A) The acceleration vector points opposite to the velocity vector on the way up and in the same direction as the velocity vector on the way down.
(B) The speed at the top of the trajectory is zero.
(C) The object’s total speed remains constant during the entire flight.
(D) The vertical speed decreases on the way up and increases on the way down.

Khoobchandra Agrawal · Accepted Answer

Hi everyone. This is the problem based on rejecting mission When a particle it&#x27;s projected from the original add angle theater under gravity. Then the part followed by it its parabolic and it is called projectile motion. In this problem, it is given our projectile is projected Add angle 45 degrees. Okay. In the first part it is given the acceleration right points approach it toe velocity on the way up man, it is moving up than acceleration A project, a velocity and same direction Off velocity on We don&#x27;t let us hear the solution. This statement is wrong. This about a statement is wrong Here Acceleration is equal toe acceleration due to gravity which always directed vertically don&#x27;t work hence acceleration G is a project toe vertical component off velocity on the up and same direction Oh, vertical component off velocity on the way down so above the statement is wrong. No, second be second statement is given. Velocity is zero at the top off trajectory. This is wrong because at the top off trajectory at the top off the trajectory Vertical component off velocity zero But hurry gentle component is non zero Hence velocity couldn&#x27;t video Now third escape me Total velocity. Sorry. Total speed remains constant during entire flight because this is wrong, because origin, it&#x27;ll velocity remains constant. What vertical component of velocity keeps on changing do toe acceleration due to gravity. The last option deep. It is given the vertical SPD, um, decreases on the way up and increase its on the way down. This is correct, because acceleration due to gravity G is a project toe vertical component off velocity during upward motion. Um, G is in same direction off vertical component of velocity during downward motion. Hence, do you option is correct, that&#x27;s all. Thanks for watching it.

Salamat Ali · Answer

for the projectile for a projectile trajectory in the epics the lost he&#x27;s momentarily zero s o. The answer is okay. Where is the acceleration is a constant. Uh, So, um, but see is wrong. Projectile maximum kind. Take energy. That packs is wrong. And but B is wrong. So what is the right answer?

Ze-Han Lee · Answer

so in this problem, Uh, so we have a predictable Yeah. So this is the trajectory. Yeah. So, uh, we want to know under this Ah, movement. So which one? Which compote? Wheat. I mean, which variable remains constant. So the 1st 1 says the horizontal component off the velocity. So this is a constant because there is no any acceleration on the horizontal direction. Right? So the VX is a constant. That is right. And the 2nd 1 says that to the vertical component of the velocity. So as you can see that the we have gravity, Ray and the gravity is pointing down. So that says we have acceleration, which is pointing down so b y has to change. So the wife is not a constant. Okay? And that one stays Ah, uh, X generation. The federation is a constant because it is always pointing down and the magnitude is always equal g. Okay, so this is right. So, for this problem, when three there. Right. Okay,

Abhishek Jana · Answer

So when an object is thrown upwards during his entire part of the motion, the ax elation events constant even if, ah, at the maximum height where velocity becomes zero, we still have the X elation with is roughly 10 meters per second squared. So Option E is the correct answer. Thank you.

Ze-Han Lee · Answer

So in this problem, uh, we have four statements. So in the 1st 8 many states that Ava objects center rations, counted it, then muster moving the straight line. So this is not right because he gave you threw a ball from the ground and see that the acceleration is constant. Which evil G but to the movement is not straight line. All right, it&#x27;s ah, it&#x27;s a projectile. So in part B in the choice B, I says even objects acceleration zero. Then the speed might must have returned. Constant constant. That s o This is right. So the choice bees, right. His choice, eh? And chose. C says that if the object of speed return constant, then the generation must be zero. This is not right. So if you look at ah ah, circular moat if you look at the second movement, so see that to the the The speed is a constant, but to the acceleration is no zero. There is a fine it. Ah, centripetal acceleration. Okay. And in part d say&#x27;s, uh if the objects of direction of the movement is changing the acceleration zero, that&#x27;s that. Is that this is right. Okay,

Suzanne W. · Answer

So we need to answer the following questions for projectile motion on level ground assuming negligible air resistance, with the initial angle being neither zero nor 90 part A. Is the velocity ever 0? No, it&#x27;s not. So projectile motion looks like this. So if the angle is neither zero nor 90 the velocity is never zero. When is the velocity a minimum or a maximum? It is a minimum at the apex of the trajectory and it is a maximum at launch and impact. So part C. Can the velocity ever be the same as the initial velocity at a time other than zero? So see? No, because velocity is a vector so it can never be the same as the initial velocity. Can the speed ever be the same as the initial speed at a time? Other than at T equals zero? Yes, the speed can be the same. The speed is equal to zero whenever it lands so it hits the ground is equal to zero. So this one is yes.

Problem

A stone is thrown vertically upwards with an init…

Problem 10 Easy Difficulty

Answer

Related Courses

Cracking The AP Physics 1 Exam

Related Topics

Discussion

Top Physics 101 Mechanics Educators

Elyse G.

Liev B.

Zachary M.

Meghan M.

Physics 101 Mechanics Courses

Math Review - Intro

Algebra - Example 1

Recommended Videos

Watch More Solved Questions in Chapter 3

Video Transcript

Robert Franek

Cracking The AP Physics 1 Exam

Elyse G.

Liev B.

Zachary M.

Meghan M.

Math Review - Intro

Algebra - Example 1

What do you need help with?

Textbooks

Ask a question

Courses

AI Tutor

Cracking The AP Physics 1 Exam

Elyse G.

Liev B.

Zachary M.

Meghan M.

Math Review - Intro

Algebra - Example 1

Robert FranekCracking The AP Physics 1 Exam

Elyse G.

Liev B.

Zachary M.

Meghan M.

Robert Franek

Cracking The AP Physics 1 Exam