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Which would weigh the most? Explain your thinking.(A) 1.0 L of 1.0 M NaBr(B) 500 mL of 1.0 M KCl(C) 1.0 L of 0.5 M NaOH

a. Comparing the masses of the solutions in exercises $7(A), 7(B),$ and $7(C),$ we conclude that the solution $(A) 1.0 \mathrm{L}$ of 1.0 $\mathrm{M}$ NaBr would weigh the most.b. Comparing the masses of the solutions in exercises $7(\mathrm{A}), 7(\mathrm{B}),$ and $7(\mathrm{C}),$ we conclude that the solution $(\mathrm{A}) 1.0 \mathrm{L}$ of 1.0 $\mathrm{M}$NaBr would weigh the most.c. Comparing the masses of the solutions in exercises $7(\mathrm{A}), 7(\mathrm{B}),$ and $7(\mathrm{C}),$ we conclude that the solution $(\mathrm{A}) 1.0 \mathrm{L}$ of 1.0 $\mathrm{M}$NaBr would weigh the most.

Chemistry 102

Chemistry 101

Chapter 15

Toxins in Solution

Section 4

Mystery Solutions

Solutions

Composition

Chemical reactions and Stoichiometry

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question. Number seven is an interesting problem where you really can't perform much calculations, but you can think of this conceptual E. It gives you a volume of an aqueous solution and the concentration of the acquis solution of a particular salute. For the first one, we have one leader of a one Mueller sodium bromide solution. For the second one, we have 500 mL of a one Moeller K c l. Solution. And for the last one, we have one leader of a 10.5 Moeller sodium hydroxide solution. We can eliminate the 500 mL solution immediately because we only have half the volume, as we do for A and C, So I'm just going to focus on the mass of the salute that is found in one leader of A and C A is one leader of one Mueller sodium bromide, One leader of one Mueller sodium bromide will have one mole sodium bromide or the Mueller massive sodium bromide, which is 103 g sodium. Bromide. One leader of 10.5 Mueller sodium hydroxide has 0.5 moles, sodium hydroxide or half the molar mass of sodium hydroxide, 20 g. So with both of the solutions. Being a leader, we will assume that the mass associated with water is very similar, and the only difference in the mass of the solution is going to be the mass of the salute that has been added because we add more mass salute to the sodium bromide solution than the one leader of one Moeller sodium bromide solution is going toe way the most.

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