00:01
Asked us to draw the situation.
00:02
This would be, this box would be the represent the car.
00:05
We have an, we started an x initial position of zero meters and we travel to x final.
00:11
We know that the part, part b is asking us to list all the knowns.
00:15
And so we know that for delta t, this would be 12 .0 seconds.
00:19
The acceleration in the x direction, 2 .40 meters per second squared.
00:24
And our initial velocity, zero meters per second, our initial position, zero meters per second.
00:31
For part c, we're going to use the formula, x final equals x initial plus vx initial times t plus one half times the acceleration and the extraction times t squared.
00:45
We know that x initial is zero and vx initial is zero.
00:49
So those two terms can be eliminated, and we find that our final x position would be, one half multiplied by 2 .4 meters per second squared multiplied by 12 .0 seconds quantity squared.
01:06
And we then see that the final exposition is equaling 173 meters.
01:14
These values are pretty reasonable, 2 .40 meters per second square.
01:20
That's attainable acceleration.
01:21
And this time is, of course, not extremely long...