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University of Wisconsin - Milwaukee

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Problem 42 Easy Difficulty

While flying at an altitude of $9.50 \mathrm{km},$ you look out the window at various objects on the ground. If your ability to distinguish two objects is limited only by diffraction, find the smallest separation between two objects on the ground that are distinguishable. Assume your pupil has a diameter of 4.0 $\mathrm{mm}$ and take $\lambda=575 \mathrm{nm} .$

Answer

1.67 \mathrm{m}

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Video Transcript

So in this problem, the altitude you're at from the ground is 9.5 kilometer your people. Stamina is four millimeter. The wavelength of the light to observe the two objects on the ground is 575. An animator. Now, to find the separation between those two objects using the situation when the two objects are just resolved, that is going to be data that I mean, which is going to be called s over our and we have another one definition for theta mean, which is said. I mean it calls 1.22 times web length of the light used over the air pressure diameter for this case. Okay, so if we applaud this too, we can see that as it cools. 1.22 Lambda are over D, which is going to be called a 1.22 times 5 75 times 10 do negative nine and then the radius are is 9600 meter over. He is for times 10 to the negative three and this will give us 1.7 meter from here

University of Wisconsin - Milwaukee
Top Physics 103 Educators
Elyse G.

Cornell University

LB
Liev B.

Numerade Educator

Marshall S.

University of Washington

Farnaz M.

Other Schools