00:01
Hello everyone, this is ricky, and today we're working on problem number 42.
00:06
So why does one mole of sodium chloride depress the freezing point of one kilogram of water almost twice as much as one mole of glycerin? okay, so we can do this mathematically, or somewhat proportionally, but with this formula, the freezing point depression formula.
00:27
So we can calculate the magnitude of freezing point depression by i, which is the vant conf fact, van't factor, times kf, which is the depression in freezing point constant, times m, which is the molality.
00:50
And i is equal to number of moles after dissociation over the number of moles before dissociation.
01:19
And really, it's a this factor that determines the difference in magnitude and freezing point depression between sodium chloride and glycerin...