00:01
In the given compound, nicl4, 2 negative, the oxidation state of nickel is 2 positive.
00:11
So the electronic configuration will be here 3d8 4s0.
00:22
The chlorine atom is the weak ligand, so it provides a tetrahedral field.
00:28
During the complex formation, the deorbital split, which results, in two orbitals, lower and higher energy orbitals.
00:38
The splitting can be shown as 1, 2, 3, 4, 5.
00:51
In this case, 4 electrons out of 8 in the orbital go into lower energy orbits and the remaining 4 in the higher energy level.
01:01
Among 4 electrons in the higher energy level, 2 electrons are unpaired.
01:07
Therefore, the given compound nicl 4 to negative, is paramagnetic in nature...