00:01
In the given problem, there is a physics book put on the seat of a car.
00:11
The mass of the physics book is given as 3 .80 kg.
00:18
The coefficient of static friction has been given as 0 .650 and coefficient of kinetic friction has been given as 0 .550.
00:33
So if we find the two forces of friction acting on the book in case of a motion the coefficient the force of static friction comes out to be new s into m into g means 0 .650 into 3 .80 into 9 .8 newton which comes out to be if we calculate it this is 0 .65 multiplied by 3 .8 multiplied by 9 .8 and here this force comes out to be 24 .21 newton now if we find the force of kinetic friction it will become muay into m g so 0 .550 into 3 .80 into 9 .8 newton.
01:39
It comes out to be 0 .55 multiplied by 3 .8, multiplied by 9 .8.
01:48
And here it becomes 20 .48 newton.
01:53
So these are the two forces which may act, forces of friction, which may act on the book.
02:00
Now, the car is initially moving with a speed of 72 km per hour, we can convert it into meter per second by multiple line with 5 by 18 meter per second.
02:17
And here this speed comes out to be 20 meter per second...