Will the following reactions be primarily displacement or elimination?
(a) $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{Cl}+\mathrm{I}^{-} \longrightarrow$
(b) $\left(\mathrm{CH}_3\right)_3 \mathrm{CBr}+\mathrm{CN}^{-}$(ethanol) $\longrightarrow$
(c) $\mathrm{CH}_3 \mathrm{CHBrCH}_3+\mathrm{OH}^{-}\left(\mathrm{H}_2 \mathrm{O}\right) \longrightarrow$
(d) $\mathrm{CH}_3 \mathrm{CHBrCH}_3+\mathrm{OH}^{-}$(ethanol) $\longrightarrow$
(e) $\left(\mathrm{CH}_3\right)_3 \mathrm{CBr}+\mathrm{H}_2 \mathrm{O} \longrightarrow$
(a) $\mathrm{S}_{\mathrm{N}} 2$ displacement. $\mathrm{I}^{-}$is a good nucleophile, and a poor base.
(b) E2 elimination. A $3^{\circ}$ halide and a fairly strong base.
(c) Mainly $\mathrm{S}_{\mathrm{N}} 2$ displacement.
(d) Mainly E2 elimination. A less polar solvent than that in (c) favors E2.
(e) $\mathrm{S}_{\mathrm{N}} \mathrm{I}$ displacement. $\mathrm{H}_2 \mathrm{O}$ is not basic enough to remove a proton to give elimination.