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With $A$ as in Exercise $3,$ find a nonzero vector in Nul $A$ and a nonzero vector in $\operatorname{Col} A .$

$\left[ \begin{array} { l } { 1 } \\ { 0 } \end{array} \right] \cdot \left[ \begin{array} { l } { 3 } \\ { 1 } \end{array} \right]$

Calculus 3

Chapter 4

Vector Spaces

Section 2

Null Spaces, Column Spaces, and Linear Transformations

Vectors

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University of Michigan - Ann Arbor

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Lectures

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In mathematics, a vector (…

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With $A$ as in Exercise 17…

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For $A$ as in Exercise $12…

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Construct a nonzero $3 \ti…

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Construct a $3 \times 3$ m…

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If $ a = \langle 3, 0, -1 …

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Show that $ 0 \times a = 0…

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Show that $0 \times \mathb…

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In Exercises $3-6,$ find a…

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in this problem. We're asked to use men Take saying from exercise tree and they were asked to find knows your victory and no, they don't. They're vectoring problem. Hey, so many column is actually a nuncio vector in call eight. So is an answer to properly It could be any Cole. No, partly a time. Thanks. I should say zero. So then the system is your enroll. Echo for will be 1001 negative seven or 6200 The way I got this is I said near Rome or will be row one minus three row too. So now we have a system off recreations here. We can say that Explorer is equal to seven x three Minus execs or and x two, The sequel to Negative four X Tree. It's a negative two plus two eggs for now. Thanks. What? The next two depends on x three MX four but X three units for our our free breakables. So plus, assume a three is one and x four is one that from you questions second equation you find next to to be 94 plus do like a dream. And from the 1st 1 We plan X one to be 7.6. That is one. So what? And we find the zonal director to be one naked too. 11

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