Question
With what minimum acceleration can a fireman slide down a rope whose breaking strength is two third of his weight?(a) $\frac{g}{2}$(b) $\frac{2}{3} g$(c) $\frac{3}{2} g$(d) $\frac{g}{3}$
Step 1
The weight of the fireman is given by $mg$, where $m$ is the mass of the fireman and $g$ is the acceleration due to gravity. Therefore, the maximum tension, $T_{max}$, that the rope can withstand is $\frac{2}{3}mg$. Show more…
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