Question
Without dividing out, find the remainder when $2 x^{2}-3 x+4$ is divided by $(x-2)$By the remainder theorem, the remainder is given by $a p^{2}+b p+c$, where $a=2, b=-3, c=4$ and $p=2$. Hence the remainder is:$$2(2)^{2}+(-3)(2)+4=8-6+4=6$$
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Here, $a=2$, $b=-3$, and $c=4$. Show more…
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