Without doing any calculations, determine the sign of Ssys...

Name: Problem 38, Chapter 18: Chemistry: Structure and Properties
Uploaded: 2019-08-10T17:17:25-08:00
Duration: 5 min 34 s
Channel: Kevin Chimex
Description: Without doing any calculations, determine the sign of Ssys and Ssurr for each chemical reaction. In addition, predict under what temperatures (all temperatures, low temperatures, or high temperatures), if any, the reaction is spontaneous.

Without doing any calculations, determine the sign of Ssys and Ssurr for each chemical reaction. In addition, predict under what temperatures (all temperatures, low temperatures, or high temperatures), if any, the reaction is spontaneous.

Transcript

00:02 So this question wants us to determine if the reaction is spontaneous or it is non -spontaneous without doing any calculation at high temperature or low temperature or at hot temperature.

00:20 So the first one is the reaction between co gas plus o2 to give to co2 and the delta h standard for the reaction is minus 56, minus 566.

00:30 0 .0 kilo.

00:33 So the first thing is to know that delta g is cost to delta h minus t that has and in this case our delta h is negative minus t which is temperature and this is supposed to be standard.

00:50 So here to the terminal delta has we know that two co gas molecule plus one oxygen gas molecule and two co2 gas molecule and two co2 therefore, the delta has will be s final minus s in the share, which is 2 minus 3 and that is supposed to minus 1, and that is negative.

01:12 So delta has negative, so if we put t multiplied by negative, then we're going to have negative plus t.

01:26 So if t is small, then delta g will be negative.

01:32 And if t is that big then dltg will be positive.

01:39 So for this reaction, for spontaneity, if temperature is small.

01:46 So this reaction is spontaneous if the temperature is small or low.

01:52 And the next one is a reaction of 2n02 to go to 2no gas plus o2.

01:58 So again, deltig is because of dlh minus t, deltas.

02:03 And delta hg is positive and minus t and delta h s here we have two no two gas and then two no gas and one oxygen gas so as final minus s in a share rate three minus two and that is positive so plus positive delta h s so this would be positive minus t so delta g would then be equal to if t is small then delta g will be positive and if t is big then delta g will be negative so the reaction is spontaneous when temperature is higher okay the next one is the reaction between h2 gas plus oxygen and that this goes to the h minus t, dota h again yeah that's h is negative and temperature multiply delta h is we know that we have two hydrogen gas and one oxygen and then two water molecules so all together we're going from three to two so s -finar is two and s initial is three and this would be negative so delta h s is negative and that minus negative and that would plus t so delta g if t is small then uh delta g is negative if t is big then delta g is positive...

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