Refer a friend and earn $50 when they subscribe to an annual planRefer Now
Get the answer to your homework problem.
Like
Report
Without solving each equation, find the sum and product of the roots.$5 x^{2}+2 x-10=0$
$\operatorname{sum}=-\frac{2}{5}$product $=-2$
Algebra
Chapter 5
QUADRATIC FUNCTIONS AND COMPLEX NUMBERS
Section 7
Sum and Product of the Roots of a Quadratic Equation
Equations and Inequalities
Quadratic Functions
Complex Numbers
Polynomials
Missouri State University
Oregon State University
Baylor University
Idaho State University
Lectures
01:32
In mathematics, the absolu…
01:11
01:00
Without solving each equat…
02:39
Find the roots of each pol…
00:57
Solve each equation using …
02:33
00:53
00:46
00:50
01:18
Find all real solutions of…
01:27
Solve each equation by fac…
he said. Today we're solving for the someone product of the roots without actually solving the equation. So let's just get right to We have five x Square plus two x minus 10. The equal zero. All right, so we begin. We know that are some is just taking the coefficients in the ratio of minus B over a. And the product is taking the coefficients in the ratio of just seeded by day. They're just identifying coefficients, and we'd be finished. We have that. My B would be too. So we have a minus two in the numerator and a is just five. And then for a product we have, that sea is going to be a minus 10 on again. There's still five, so just simple. Fine. We have minus 2/5 and we have the minus two
View More Answers From This Book
Find Another Textbook
In mathematics, the absolute value or modulus |x| of a real number x is its …
Without solving each equation, find the sum and product of the roots.$x^…
Find the roots of each polynomial equation.$$x^{3}-2 x^{2}+5 x-10=0<…
Without solving each equation, find the sum and product of the roots.$\f…
Solve each equation using the quadratic formula. Simplify solutions, if poss…
Find all real solutions of the equation by factoring.$$(5 x+1)^{2}+3…
Solve each equation by factoring.$$2 x^{2}-5 x+2=0$$
00:59
In $26-37,$ find each product.$$(4-5 i)(3-2 i)$$
01:55
In $38-45,$ find the multiplicative inverse of each of the following in $a+b…
02:29
In $46-60,$ write each quotient in $a+b i$ form.$$(10+5 i) \div(1+2 …
01:50
In $24-26,$ sketch the inverse of the given function.(SKETCH NOT COPY)…
05:35
In $18-35,$ find each common solution algebraically. Express irrational root…
01:58
04:47
When the function $g(x)=x^{2}+8 x+18$ is restricted to the interval $x \geq …
01:46
In $3-14,$ use the quadratic formula to find the imaginary roots of each equ…
Ethan said that the square of any pure imaginary number is a negative real n…
01:06
In $18-25,$ write the complex conjugate of each number.$$3+4 i$$…
92% of Numerade students report better grades.
Try Numerade Free for 30 Days. You can cancel at any time.
Annual
0.00/mo 0.00/mo
Billed annually at 0.00/yr after free trial
Monthly
0.00/mo
Billed monthly at 0.00/mo after free trial
Earn better grades with our study tools:
Textbooks
Video lessons matched directly to the problems in your textbooks.
Ask a Question
Can't find a question? Ask our 30,000+ educators for help.
Courses
Watch full-length courses, covering key principles and concepts.
AI Tutor
Receive weekly guidance from the world’s first A.I. Tutor, Ace.
30 day free trial, then pay 0.00/month
30 day free trial, then pay 0.00/year
You can cancel anytime
OR PAY WITH
Your subscription has started!
The number 2 is also the smallest & first prime number (since every other even number is divisible by two).
If you write pi (to the first two decimal places of 3.14) backwards, in big, block letters it actually reads "PIE".
Receive weekly guidance from the world's first A.I. Tutor, Ace.
Mount Everest weighs an estimated 357 trillion pounds
Snapshot a problem with the Numerade app, and we'll give you the video solution.
A cheetah can run up to 76 miles per hour, and can go from 0 to 60 miles per hour in less than three seconds.
Back in a jiffy? You'd better be fast! A "jiffy" is an actual length of time, equal to about 1/100th of a second.