Question
Work done per mole in an isothermal ? change is(A) RT log $_{e}\left(\mathrm{v}_{2} / \mathrm{v}_{1}\right)$(B) $\mathrm{RT} \log _{10}\left(\mathrm{v}_{2} / \mathrm{v}_{1}\right)$(C) RT $\log _{10}\left(\mathrm{v}_{1} / \mathrm{v}_{2}\right)$(D) RT $\log _{\mathrm{e}}\left(\mathrm{v}_{1} / \mathrm{v}_{2}\right)$
Step 1
Step 1: We know that for an ideal gas, the equation of state is given by $pV = nRT$, where $p$ is the pressure, $V$ is the volume, $n$ is the number of moles, $R$ is the gas constant, and $T$ is the temperature. Show more…
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$\mu$ moles of gas expands from volume $\mathrm{V}_{1}$ to $\mathrm{V}_{2}$ at constant temperature $\mathrm{T}$. The work done by the gas is (A) $\mu \mathrm{RT}\left\{\mathrm{V}_{2} / \mathrm{V}_{1}\right\}$ (B) $\mu \operatorname{RTln}\left\{\mathrm{V}_{2} / \mathrm{V}_{1}\right\}$ (C) $\mu \mathrm{RT}\left\{\left(\mathrm{V}_{\mathrm{v}} / \mathrm{V}_{1}\right)-1\right\}$ (D) $\mu \operatorname{RTln}\left\{\left(\mathrm{V}_{2} / \mathrm{V}_{1}\right)\right.$
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