Question
Work each of the following.Suppose that a circle is tangent to both axes, is in the third quadrant, and has radius$\sqrt{2} .$ Find the center-radius form of its equation.
Step 1
This means that the center of the circle is at a point where the x-coordinate and y-coordinate are both equal to the negative of the radius. Since the radius is $\sqrt{2}$, the center of the circle is at point $(-\sqrt{2}, -\sqrt{2})$. Show more…
Show all steps
Your feedback will help us improve your experience
Swati Agarwal and 89 other Algebra educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Suppose that a circle is tangent to both axes, is in the third quadrant, and has radius $\sqrt{2} .$ Find the center-radius form of its equation.
Graphs and Functions
Circles
Work each of the following. Find the center-radius form of the equation of a circle with center $(3,2)$ and tangent to the $x$ -axis. (Hint: A line tangent to a circle touches it at exactly one point.)
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD