00:01
All right, to this question, we are given a number of atoms and we are asked to predict whether they will gain or lose electrons when they form ions.
00:09
So first up, we have radon.
00:12
Now, the first step to answering a question like this is to find it on the periodic table.
00:18
Sorry, it's not radon, it's radium.
00:20
It's over here, right there.
00:22
It's in group 2a.
00:24
That means it has two valence electrons.
00:26
Now remember, items in group 2a like to lose their electrons.
00:31
So that they can form a stable octet.
00:33
If radium loses its two electrons, it'll have the same configuration as radon.
00:42
So we would expect radium to form an ra2 minus ion 2 -2 -plus.
00:50
Because it loses electrons, so it will have more protons than electrons, so it'll have a positive charge.
00:56
There we go.
00:58
Next, we have i -n.
01:01
And this is awkward because i don't know.
01:04
Oh, here it is.
01:05
Iridium.
01:06
Okay.
01:07
It's in the same group as boron, aluminum, and gallium.
01:13
Remember, elements are trying to get to a stable octet.
01:18
Iridium has three valence electrons.
01:20
It's easier to lose electrons at this point than to try to gain them to make eight.
01:27
So with three valence electrons, it's easier to lose three than to gain five.
01:31
So we would expect iridium to form a 3 plus ion by losing 3 electrons.
01:40
Let me just delete this arrow in a second.
01:43
Okay...