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$w^{\prime \prime}+w=u(t-2)-u(t-4)$ $w(0)=1, \quad w^{\prime}(0)=0$

$u(t-2)-u(t-2) \cos (t-2)-u(t-4)+u(t-4) \cos (t-4)+\cos t$

Algebra

Chapter 7

Laplace Transforms

Section 6

Transforms of Discontinuous Functions

Polynomials

Oregon State University

Baylor University

University of Michigan - Ann Arbor

Lectures

03:50

$$w^{\prime \prime}+w=t^{2…

05:17

$$w^{\prime \prime}-4 w^{\…

02:56

$w^{\prime \prime}-x^{2} w…

05:57

$w^{\prime \prime}+3 x w^{…

03:32

$$\begin{array}{l}{w^{\pri…

07:25

$$x w^{\prime \prime}-w^{\…

03:48

$$e^{x y} \sinh w-z^{2…

01:54

$\frac{d^{2} w}{d t^{2}}+\…

$$w^{\prime \prime}+4 w^{\…

01:06

If $u(x)=r(w(x))$ and if $…

02:40

$$w^{\prime \prime}+w=\del…

$\mathbf{x}^{\prime}=\left…

Okay, so we're gonna ply the love the transformer on both sides. And this will give us lf habitable front force w equals to l a few of t minus two months. You have t months four. Okay, so that reads a square comes w mines as pull us w It goes to eat tonight with us, my n'est eating who for us over s but that we have w equals suit as the westward plus one poor's e typical to us times one minus e to break us over s times s word. Close one. So inside we can actually have the partial Russian mechanization. And that's gonna be so We keep the top and we decompose the bottom. So that's the vehicles to this firm Times when they were asked, minus ass over as squared plus one, which is easier for put up performing the universal applause transform. Okay, so now apply the inverse of us too. W of s And, uh, Then it was too co sign. See? Plus, you have teeth. Money's too. Times one is one minus co sign of team on this too. Minus one month's co sign of tea months. Four times you have two months. Four. So that's way applied through a mate from the text

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