00:01
Alright, so let's balance a few chemical equations.
00:05
I told that di -nitrogen pentoxide reacts with sodium metal to produce sodium nitrate and nitrogen dioxide.
00:13
So, dye -nitrogen, that's n2, pentoxide, which is 05, and we need to put that that's a gas.
00:28
It's going to react with sodium, which is a solid.
00:34
And this will produce sodium nitrate and nitrogen dioxide nitrate is an n -o -3 group so sodium nitrate will be n -a n -o -3 and this is going to be a solid and then next we have nitrogen dioxide simply n -o -2 so we need to make sure this equation is balanced so on the left side, you can see that we have two nitrogen.
01:23
We have one, two nitrogen on the right.
01:26
Five oxygen on the left, three from the nitrate, two from the dioxide.
01:30
So that's five on the right as well.
01:33
And then, yeah, let me put that this as a gas.
01:37
Always remember to put your states of matter.
01:39
And then finally we have one sodium on the left, one sodium on the right.
01:43
So this is our balanced chemical equation.
01:47
Next, we're told a mixture of nitric acid and nitrous acid formed when water reacts with dinitrogen tetroxide.
01:59
Now, since we're forming nitric and nitrous acid, these compounds are going to be on the product side of the equation.
02:08
So let's go ahead and draw our arrow here.
02:13
And nitric acid is going to be an acid.
02:19
So it's going to have a hydrogen in it...