Problem

Which is the stronger acid, $\mathrm{H}_{2} \math…

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Problem 88 Easy Difficulty

Write a balanced chemical equation for the reaction of an excess of oxygen with each of the following.
Remember that oxygen is a strong oxidizing agent and tends to oxidize an element to its maximum oxidation state.
(a) $\mathrm{Mg}$
(b) $\mathrm{Rb}$
(c) $\mathrm{Ga}$
(d) $\mathrm{C}_{2} \mathrm{H}_{2}$
(e) $\mathrm{CO}$

Answer

a. $2 \mathrm{Mg}(s)+\mathrm{O}_{2}(g) \rightarrow 2 \mathrm{MgO}(s)$
b. $\mathrm{Rb}(s)+\mathrm{O}_{2}(g) \rightarrow \mathrm{RbO}_{2}(s)$
c. $2 \mathrm{Ga}(s)+3 \mathrm{O}_{2}(g) \rightarrow \mathrm{Ga}_{2} \mathrm{O}_{3}(s)$
d. $2 \mathrm{C}_{2} \mathrm{H}_{2}(g)+5 \mathrm{O}_{2}(g) \rightarrow 4 \mathrm{CO}_{2}(g)+2 \mathrm{H}_{2} \mathrm{O}(l)$
e. $2 \mathrm{CO}(g)+\mathrm{O}_{2}(g) \rightarrow 2 \mathrm{CO}_{2}(g)$

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Chemistry 101

Chemistry

Chapter 18

Representative Metals, Metalloids, and Nonmetals

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Video Transcript

question. Number 88 is mostly a balancing of a chemical reaction question. However, you do need to remember that we are reacting oxygen, which is a strong oxidizer with a compound producing the highest oxidation state for that particular compound or element. So before balancing it, you need to identify what the product will be, which will have the highest oxidation state of the element that is involved in the reaction with oxygen. So, for example, when magnesium reacts with oxygen, its highest oxidation state is too. So it's going to form a product that has magnesium with an oxidation state of plus two, which would be magnesium oxide. We then balance this by putting it to in front of the magnesium oxide, so we have to Oxygen's will then need to put a two here so we have to magnesium. Then we have rubidium reacting with oxygen. The maximum oxidation state of rubidium is one plus, so we're going to need to rub idioms for every oxygen that has a charge of two minus. We then need to place a four in front of the rubidium and a two in front of the rubidium oxide, so we have an even number of oxygen's, which then allows us to have the chemical reaction balanced for rob idioms, for rob idioms to oxygen's to Oxygen's for the next one, we have gallium reacting with oxygen. Its highest oxidation state is three. So we're going to produce gallium oxide, which is G A 203 A three plus charge multiplied by two gives us six plus and a three multiplied by the Tu minus of oxygen gives us six minus. We're then going to need to put a two in front of the gallium oxide that gives us four gallium. So we need a four in front of the gallium here. We had to put a two here so we'd have an even number six of Oxygen's so we could put a three in front of the 02 Then we have C two h two reacting with oxygen. This is a combustion reaction producing carbon dioxide and water To balance it, we're going to need to put a two in front of Theus. Settling. That gives us four carbon, so we'll put a four in front of the carbon dioxide. We now have four hydrogen, so we need to put a two right there. This four in front of carbon dioxide was done so we could get uneven number of oxygen's. We now have 10, so we could put a five here, so we have 10 oxygen's on the left hand side. And for the last one, carbon monoxide reacts with oxygen to produce carbon dioxide, and it's balanced by putting a two in front of the carbon monoxide and the carbon dioxide.

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