00:02
The purpose of this problem is to recognize the organic reactions and write the balance equation and know the kind of reaction that it belongs to.
00:22
So let's see the first one is we have 3 -3 -dimetro 1 -butin.
00:33
So we're going to write down the formula.
00:35
The structure formula is, let's write the backbone first.
00:43
It's one futein, so the double bond is here, and three -three dimethyl, so one ch3 here, another one, ch3 here.
00:57
And we'll finish by adding hydrogen, okay, and it reacts with acid, and the to produce another formula, which is 2 -3 dimethyl 2 -butin.
01:23
It's still but the double bond change the position.
01:30
So double bond is on the second carbon.
01:34
So that's 2 -butin.
01:36
And the dimethyl groups are on 2 and 3.
01:41
So one is here.
01:43
One is still on carbon number three and then we'll add the hydrogen for the atom for the carbon okay and what's the difference we'll see we have if we write the molecular formula they are the same they're just the position of double bond and the method group have changed so this is rearrangement because nothing is added or removed okay the molecular formula will be the same next one is we have one iodot 2 -2 dimethyl protein so we're right now the formula propine which means three carbon one is propane, propane, say there's no double bond or triple bond.
03:02
And one idle, which means on carbon number one, that's an iodine atom there, and two to dimethyl.
03:14
So one here, one here, and finish up by adding the hydrogen, okay, add a two hydrogen here, and this will react with water and produce 2 -2 -diamethyl 1 -prolone.
03:40
1 -pupino which means there is an alcohol group oh on carbon number 1, and then 2 -2 -diamethyl, ch3, ch3 here, finish up by adding the hydrogen.
04:02
And then hydrogen iodide...