write-a-balanced-chemical-equation-to-describe-what-happens-as-the-color-changes-from-yellow-to-re-2

Name: write a balanced chemical equation to describe what happens as the color changes from yellow to re 2
Uploaded: 2020-10-24
Duration: 1 min 35 s
Channel: Numerade
Description: Write a balanced chemical equation to describe what happens as the color changes from yellow to red for methyl red indicator.

Question

Write a balanced chemical equation to describe what happens as the color changes from yellow to red for methyl red indicator.

Michelle Pribek · Accepted Answer

So this question asks us to write a balanced chemical equation to describe what happens as the color changes from yellow to red form Ethelred Indicator. So in the previous problem, E guess we just answered both eso I&#x27;ll just review um, the general abbreviation for an indicator molecule is h i n. So, in a basic solution, we start with the indicator molecule represented here on the white board. H i n. It dissociates into hydrogen ions, an indicator, and ions which reflects yellow in acidic solution. The reverse happens, so we have hydrogen ions, an indicator and ions forming the indicator molecule represented as h i n. And that reflects red light. So we see a red color and there you have it.

Kim Trang Nguyen · Answer

and the problem. 11. They give you the picture, right? But we have toe violence in the equation. Usually us close fear No. They send for nitrogen dress They sent for oxygen and white. They send full hydrogen and therefore you can write a question in this element. Single like this hydrazine react with di di nitrogen. Their job side and you get the product is water and magic and gas. They This is unbalanced equation. So before the abandoned question you have tow Tell the number the up atom in both side. Now that the left side and the right side our nitrogen here nitrogen on the left side floor and and the rise I get to also featured on the left side that for and in the rice I got one hydrogen left side fall and writes hi to in this this element because you see on the left off oxygen outnumber the right Sorry the right side off the equation The old sacre is that part number. So I want you balance the autumn above us. That is the rule. So you look for right here, right? So now you count oxygen. Most sign oxygen equal right And now you look at the hydrogen hydrogen because you just put for on the water on you. Count the hydrogen on the left side. The right side, you see? Eight. Then that&#x27;s the only fall. So you have to go through right here. And now you see the now you can on the left side After you put your belt on hydrogen. Now you can in the left side now becomes sick, right? And adviser, only two. So we have to balance nitrogen for both are equal. So you got three right here. And now you check. Mhm. You check. I think you see hydrogen. 1910. Also region. Now you can hear hydrogen left side Ate rice. I ate right oxygen left side four and rice I four and nitrogen left side. Sick. Right side. Sick. So this equation is balanced.

Heather Gamble · Answer

in this problem, we&#x27;re balancing a Cem simple chemical reaction. The reaction between ammonia and oxygen. Cuba News my dream monoxide and water. And to begin well, the nitrogen zehr balanced initially Ah, hydrogen. We have three here and to hear and that&#x27;s not balanced. So we could write a three halves here. But that&#x27;s kind of messy because then we&#x27;d have happen old two year. So I&#x27;m going to put a three here which makes two times three is six. Hydrogen is, which means we needed to hear. But now our nitrogen is aren&#x27;t balanced, so we need to here. So now I two nitrogen to nitrogen six. Hydrogen, six hydrogen. But let&#x27;s count oxygen. Here we have to oxygen&#x27;s and here we have three oxygen for a total of five, so we could fix that by putting a five halves here and then everything is balanced. But if we like the clear that fractional coefficient, which is perfectly acceptable, but it&#x27;s a little neater with it it within multiply the whole equation by two and we end up with for ammonia. Why vote to giving for Eno and sex age duel

Daniel Kim · Answer

So this question asked us to explain the steps of balancing chemical equations, so the first step is to write the unbalanced equation. So what this means is that you just need to write all of the reactant and the products, but you don&#x27;t need to include their coefficients, which means that once again, it&#x27;s not yet balance. And then the second thing that you need to do is go element by element, comparing both the reactant in the products you need to compare whether or not they&#x27;re balanced. So it&#x27;s element by element comparison. So let&#x27;s say, for example, that my arbitrary chemical equation was C D four decomposes into C. D as well as so I know that nor to balance his equation, I need to compare the elements, see on both sides and then d on both sides. Well, I know that C is balance, and then I move on to D. The idea is not balanced and your balance that I just put a three in front of their. So the element by element comparison includes counting elements and then appropriately adding coefficients. And then once you finished the final step, once you&#x27;ve put all the coefficient, and you think you counted each element by one by one. If you simply verify or check final equation to make sure that everything is balanced, and if you do these three steps, you&#x27;ll balance every chemical equation.

James Irizarry · Answer

you guys were doing. Ah, problem number 18 of chapter three of chemistry. Molecular approach. They want to write a balanced equation for each reaction. Solid copper Viets are sold. So for reform form solid copper sulfide copper one. So far so see you. So many was sell it so for yield Copper one. So far they so so for tens. Have a minus two charger. Copper&#x27;s gonna have a plus one. So we&#x27;re gonna to comfort. See you too. So fight. Sell it. So now we&#x27;re gonna need to and asked you to cover on the right. We need to have two copper on the left. And here we are. It&#x27;s bounced. So now be solid. Iron three oxide, F e 203 reacts with hydro gas to form solid iron and liquid water. Yes. So we have two on the left. We have to have two on the right. We have the reaction left. We have to have three on the right now. We have 600 on the right. We have to have sex unless it gets put. Three in front of here. All right. Next. Sulphur dioxide reactive auction gas to form. So for try outside. Okay, so we have one girlfriend left once over on the right. Wait. We have We have four options left. Three on the right. So we&#x27;re going to have get an even number of auctions on the right so we can bounce on the left. So we have to add two in front. Here comes when we have to have two in front here, too. So from left to underwrite six sections on the right, and then we have for auctions and then six Oxygen&#x27;s on left. So now gashes, ammonia, the axe for gasses, Oxygen from gashes, nitrogen monoxide and gashes Water. Now let&#x27;s bounce it. One night from the left, one on the right. We have 300 left two on the right. So once I once even so, we have to multiply This by two has got to front here. So to night. Since I&#x27;m left to on the right. Yes, 20. Yes, right. So then we have to Hodgins on the left. We&#x27;re gonna have We have 600 mil up to. We have to have two on the right. So we have to have three in front of here and you&#x27;ll notice that we have five oceans on the right. So now we have to Yes, we have to Who? Double double D&#x27;s. So that it too. We&#x27;re gonna four. And instead of three, we&#x27;re gonna have six. So for six or so for nitrates on the left, four on the right, a 12 hundreds, not 12 times on the right, one. Okay. Before, Huh? For actions here, six year. So then we have to hear. Sometimes you have to have 5502 and we&#x27;re done. It&#x27;s very straightforward. Just go through this step by step Here. What&#x27;s on the left? Figure out what&#x27;s on.

Natalie Almond · Answer

So for this problem, we&#x27;re gonna want to look at the diagrams in the book. But we do it. We want to write some balance equations am find what the Net ionic equations are so that we can identify any spectator ions. So let&#x27;s start with a so first looking at the different Adams and compounds we have in this diagram, we&#x27;re going to write a balanced chemical equation. So we know this to be see you is so fine, that is Equis. And we&#x27;re just adding the states so that we can a little bit better see what the different components are that we&#x27;re working with. So now that we have this falling balanced equation, we can look at the different parts and see what can be split into different ions. So we know that you split this up. He&#x27;s put this up. You can&#x27;t split this up, but we can also split this up, which means that we&#x27;re going to see the this component cross out with this component and are so Diem&#x27;s cross out in this component. So that being said, we can go ahead and write or net Ionic equation now going to do so in a different color student read. So we know, based on what we had left after we crossed now and expect Peter ions is our solid product. I am base on what we know that we crossed out. We know that we crossed out for Spectators. We crossed out in sodium, then in s 04 tu minus. And based on the corresponding colors, we know that the spheres for sodium or gray and the color spheres for this one are blue. Okay, so we&#x27;re gonna work on our next problem now. And in order to do so, we&#x27;re gonna look at the diagrams again because this is gonna be what we&#x27;re balancing our equation off of and how writing the equation. So we&#x27;re gonna go down a little bit so much so we have room to do be And four b looking at the diagram, we could make the following chemical equation Cool boat, chlorine. Aquarius. You know, show how I balance this as well, so you can understand what we&#x27;re doing. Just kind of write it out so that we can see regard. So you know, chloride, which is just a table salt and is Aquarius. Okay? So when looking at balancing this. I knew that we were going to need a two because not only do we have to all Christians here and the products we also have to hydrogen and the O. H is together in sodium hydroxide or reactions. So by adding a coefficient of to here to match the O. H. On the product side, I had to Sodium is on the reactive side and only one on the product side. So that&#x27;s where this second to came in from. So now that we have more fully balanced equation, what we can do next is go ahead and look at doing see net Ionic equation. So we know we have a seal on this side and on this side we have two on each side. So that means that the chlorine is going to inspect your eye on that. We can across out, and the sodium is going to be the same. We have two on each side. It&#x27;s gonna be what we cross out. So writing what we haven&#x27;t crossed out, we have cobalt two plus plus two hydroxide, and then we&#x27;re gonna leave are solid because we couldn&#x27;t break that up into ions and that&#x27;s what stays. So we found our Spectators to be sodium again and the Corina, and based on the colors we know the sodium is gray Claure is going to be green First fears And now we can we want to do the last down a little bit more so much. Okay, so we&#x27;re gonna look again of the diagrams so we can make our fully balanced equation Gonna right. The suasion itself equally is Tess, you IOD i e quiz and then looking, we have so her eye nine. And this is a solid which is important when we&#x27;re looking at our net Ionic a second my Casio tricked And this is a quiz, and this is the three. So if we look, we know we&#x27;re gonna be able to cross out Not only are nitrogen is but our oxygen&#x27;s. So these are gonna be spectator ions, and then our potassium is also gonna be Spectators. So that means we can go ahead and do silver. It&#x27;s the dine is gonna give us our solid product that we couldn&#x27;t break up into its ions. And so when we&#x27;re looking at spectator for this one, we saw that it was that potassium that we talked about talking out that are no. Three months. And we find that the past, um, is red and then we have blue here.

Problem

Research an acid-base indicator and explain how i…

Problem 5 Easy Difficulty

Write a balanced chemical equation to describe what happens as the color changes from yellow to red for methyl red indicator.

Answer

Balanced chemical equation to describe what happens as the color changes from yellow to red for methyl red indicator $\Rightarrow$
$H^{+}+I n^{-} \rightarrow H I n$

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Balanced chemical equation to describe what happens as the color changes from yellow to red for methyl red indicator $\Rightarrow$$H^{+}+I n^{-} \rightarrow H I n$

Living by Chemistry

Allea C.

Karli S.

Jacquelin H.

Jake R.

Liquids - Intro

Comparison Of Gases Liquids And Solids

Angelica M. StacyLiving by Chemistry

Allea C.

Karli S.

Jacquelin H.

Jake R.

Balanced chemical equation to describe what happens as the color changes from yellow to red for methyl red indicator $\Rightarrow$
$H^{+}+I n^{-} \rightarrow H I n$

Angelica M. Stacy

Living by Chemistry