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Write a matrix equation that determines the loop currents. [M] If MATLAB or another matrix program is available, solve the system for the loop currents.

a) $\left[\begin{array}{ccccc}{9} & {-1} & {0} & {-1} & {-4} \\ {-1} & {7} & {-2} & {0} & {-3} \\ {0} & {-2} & {10} & {-3} & {-3} \\ {-1} & {0} & {-3} & {7} & {-2} \\ {-4} & {-3} & {-3} & {-2} & {12}\end{array}\right]\left[\begin{array}{c}{I_{1}} \\ {I_{2}} \\ {I_{3}} \\ {I_{4}} \\ {I_{5}}\end{array}\right]=\left[\begin{array}{c}{50} \\ {-30} \\ {20} \\ {-40} \\ {0}\end{array}\right]$b) $I_{1}=4.00 \mathrm{A}$$I_{2}=-4.38 \mathrm{A}$$I_{3}=-0.90 \mathrm{A}$$I_{4}=-5.80 \mathrm{A}$$I_{5}=-0.96 \mathrm{A}$

Algebra

Chapter 1

Linear Equations in Linear Algebra

Section 10

Linear Models in Business, Science, and Engineering

Introduction to Matrices

Missouri State University

McMaster University

Harvey Mudd College

Baylor University

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01:32

In mathematics, the absolu…

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okay in this program where? Use the curtain off formula. What age? Because to the total current times your total resistance. Um, so we have five different lobes in a way that means we have five different immune equations. So for the first GOP at NYU, I want minus eyes. I tu minus. I fall minus four times I five because 2 50 the second group minus. I want cross seven. I tu minus twice off I three minus three. I five equals to 30 so he should be minus 30. So be careful about this. On the direction of the ah batteries, I eyes different with the direction of current. That means we have a miner's in front off this wattage for the third group minus two. I two pass tonight three minus three. High four minus three. I five equals to 20. The next group we'll be miners. I want minus three. I three process seven I four miners 25 because to minus 40. So there's another 90. If sign here for the same reason. And for the last hope, we don't have any pottage. That means the total body gee, close to zero, and we can convert this system of equations into matrix form by collecting off its coefficient. Yes, we have. No, I minus 10 minus 14 So I can see that this coefficient metrics is, in fact symmetric, not deprived by, um, the variables. I want to high five. You closed to the wattage, and we can use, um calculator to figure out on the solution. Justin, put this matrix into the calculator. We have I one equals 24 0.0 to a close to minus 4.38 Hi. Three close to minus 2.90 I fall. He caused to a minus 5.0. And I five equals two miners. Your point. Nice six. So this is a solution to this. It's not be prisons.

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