Question
Write a plausible Lewis structure for $\mathrm{C}_{3} \mathrm{O}_{2},$ a substance known as carbon suboxide.
Step 1
Count the total number of valence electrons: Carbon has 4 valence electrons, and Oxygen has 6 valence electrons. So, for C3O2, we have a total of (3 × 4) + (2 × 6) = 12 + 12 = 24 valence electrons. Show more…
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