00:01
Hello, so we let a, b, the bin one has one ball, and b, be exactly one ball, fell into bins, one, two, or three.
00:10
So for part a, given b, the one ball is equally likely to be in either bin one, two, or three.
00:24
So therefore, the answer there is going to be one -third, since they're all equally likely.
00:30
Be given that two, given that bin two receive no balls, each ball is now going to be equally likely to be in any of the other n minus one bins.
00:41
So then for each ball, the probability that the ball goes into bin one, given that it's not in bin two, is going to be one over n minus one...