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Write a quadratic equation with integer coefficie…

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Problem 1 Problem 2 Problem 3 Problem 4 Problem 5 Problem 6 Problem 7 Problem 8 Problem 9 Problem 10 Problem 11 Problem 12 Problem 13 Problem 14 Problem 15 Problem 16 Problem 17 Problem 18 Problem 19 Problem 20 Problem 21 Problem 22 Problem 23 Problem 24 Problem 25 Problem 26 Problem 27 Problem 28 Problem 29 Problem 30 Problem 31 Problem 32 Problem 33 Problem 34 Problem 35 Problem 36 Problem 37 Problem 38 Problem 39 Problem 40 Problem 41 Problem 42 Problem 43 Problem 44 Problem 45 Problem 46 Problem 47 Problem 48

Problem 31 Medium Difficulty

Write a quadratic equation with integer coefficients for each pair of roots.
$4,7$

Answer

$x^{2}-11 x+28=0$

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Algebra

Algebra 2 and Trigonometry

Chapter 5

QUADRATIC FUNCTIONS AND COMPLEX NUMBERS

Section 7

Sum and Product of the Roots of a Quadratic Equation

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Watch More Solved Questions in Chapter 5

Problem 1
Problem 2
Problem 3
Problem 4
Problem 5
Problem 6
Problem 7
Problem 8
Problem 9
Problem 10
Problem 11
Problem 12
Problem 13
Problem 14
Problem 15
Problem 16
Problem 17
Problem 18
Problem 19
Problem 20
Problem 21
Problem 22
Problem 23
Problem 24
Problem 25
Problem 26
Problem 27
Problem 28
Problem 29
Problem 30
Problem 31
Problem 32
Problem 33
Problem 34
Problem 35
Problem 36
Problem 37
Problem 38
Problem 39
Problem 40
Problem 41
Problem 42
Problem 43
Problem 44
Problem 45
Problem 46
Problem 47
Problem 48

Video Transcript

to write a quadratic equation. Knowing Route one and route to are equal to four and seven and so four plus seven is gonna equal negative be over a and four plus seven is equal to 11. Right? So how do we make this equal negative? Be over a, well, highly recommend. We just say that a equals one Our lives are gonna be so much easier for this and this equation if a equals want. And so that means our be value to satisfy this would have to be a negative 11 because the negative negative 11 gives us is possible 11 that we want. All right, so then the product, a little bit simple four times seven equals 28. And if a is one, then see is 28/1. This works so often a value of one. There's no coefficient of X squared B value of negative 11. Let me change that. Plus to a minus minus 11 x in a see value. The positive 28 set equal to zero

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