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Write a system of two equations in two variables to solve each problem.Geometry. A 50 -meter path surrounds a rectangular garden. The width of the garden is two-thirds its length. Find the length and width.
Length: $15 \mathrm{m},$ width: $10 \mathrm{m}$
Algebra
Chapter 4
Systems of Linear Equations and Inequalities
Section 4
Problem Solving Using Systems of Equations
Equations and Inequalities
Systems of Equations and Inequalities
Missouri State University
Campbell University
University of Michigan - Ann Arbor
Idaho State University
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So you have a rectangular situation. 50 meter path surrounds a rectangle. Your rectangular gardens. Let's say you got length with link with Selina, it's a 50 meter path, and that would mean you have to go to lengths close to is to lock around. It's the perimeter. The width is 2/3 its length. So the with is 2/3 will link. This looks like substitution for me. Substitute the 2/3 in for the W right there because W is equal to 2/3 of L. So 50 equals two hour plus two times w We're substituting in t thirds. L multiply the two in the two theories to our plus 4/3. Now, um, Now, if you think about thirds, we need a common denominator here. So to make two l into thirds right now, it's too well over one. And so I'm gonna multiply by three because then my denominator will be three. So I have 50 equal six al over three plus 4/3 l for l over three. So I'm gonna bring that over here. 50 equals six and four makes 10 l over three so you can divide both science by 13th if using a calculator, make sure you, uh, put the 13th infraction form. That'll give you 15 I believe. Yeah. So 15 would be the l. And then if you want to find the W w. Is 2/3 of that. Well, 2/3 of 15 is 10 and you can double check that. That has a perimeter.
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