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Write a system of two equations in two variables to solve each problem.Thanksgiving Dinner. There are a total of 510 calories in 6 ounces of turkey and one slice of pumpkin pie. There are a total of 580 calories in 4 ounces of turkey and two slices of pumpkin pie. How many calories are there in 1 ounce of turkey and in one slice of pumpkin pie?
$$55 \text { calories }$$ $$\text { 180 calories }$$
Algebra
Chapter 4
Systems of Linear Equations and Inequalities
Section 4
Problem Solving Using Systems of Equations
Equations and Inequalities
Systems of Equations and Inequalities
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Campbell University
Oregon State University
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we got? What is it? Thanksgiving dinner. We got 510 calories, Six ounces of turkey, one slice of pumpkin pie. I'm just gonna go six ounces of turkey, one slice of pumpkin pie, six ounces a turkey and one size makes 5 10 then the other 580 calories in four ounces of turkey and two slices of broken pie. So four turkey plus two pumpkin pie equals 580. The only double check. I wrote it down. Looks good. If you notice here, um, I could do elimination. And nice trick is multiplying the top equation by two. Where'd I get the two from? Because then that's gonna match up the number of peace here. It's gonna rewrite this equation right down there. Two times six, two times one two times 5 10 makes 1000 and 20. Then you can subtract the two equations from each other. So 14 minus 12 t is negative. 82 p minus. Toupee is eliminated. Then we have 5 80 minus 10. 20. Let's see a much is that 440. That look right? Yeah. So negative. 440. Divide by negative. Eight. You have your tea value, So T let's see. What is that? 51 55? Yeah, that makes sense to me. And then once you know T is 55 substitute that backyards. We just divide that their substitute teak was 55. So we have six announces a turkey plus one p equals 5 10 That's the original top equation. Six times 55 iss 330 So 330 plus ps 5 10 subtracting 330 See What does that make? P equals 180. So Turkey's 55 cows and Alison
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