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Hello everyone.
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Given a graph, g, we count the number of vertices, also known as v, and edges, also known as e.
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In a tree, a minimally connected graph, the number of edges is always one less than the number of vertices, i .e.
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The first equation, e equals v minus 1.
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If e is greater than v minus 1, which is given by the second equation, the graph must contain at least one cycle.
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So let's do equals one cycle.
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Next, we want to apply the condition to the given graph.
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Graph.
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The number of vertices, or v, is equal to 4, and the number of edges, e, is calculated by counting all connections and dividing by 2.
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Since each edge is counted twice in an undirected graph, the total count is 4...