00:01
In this problem, we're asked to find the equation of a circle that is in quadrant 1, radius of 5 units, and tangent to the lines x equals 2 and y equals 3.
00:11
So, first of all, to understand what quadrant we are in, we are in this top right quadrant, which means both our x and y values for our center will be positive.
00:24
And we're given a radius of five units and these tangent lines x equals two and y equals three and what that means is for our circle it touches these two lines at its edges so it's the farthest that our circle goes from the center so to find the equation of a circle we have the quantity x minus h squared plus the quantity y minus k squared equals r squared and our center is given by h comma k and so in our equation we have our value for r squared and we have x and y we just leave those as variables so all we need to do is find the center of our circle so if we come down here to a slightly larger graph um here we have, again, our tangent lines, x equals two and y equals three.
01:34
And we can use these tangent lines to find our center.
01:38
So we know that where our circle touches this tangent line is the farthest that our circle goes, which means wherever our circle touches the tangent line, that has to be five units from the center.
01:59
So what we can do is starting where our two tangent lines meet up, we can count five units out from both of these lines to find our center.
02:13
So if we go ahead and do that and we start from y equals three, we can find how.
02:20
High our radius goes from this tangent line.
02:28
So if we go up one, two, three, four, five, this is the height of our center...