00:03
Okay, so to solve this problem, we need to look at table 19 -13 and look at the methods of preparation, translating them from english to chemistry.
00:15
So we need to do this for antimony and bismuth.
00:19
Let's start with antimony.
00:21
So i've written out most of it here, but i'll walk you through it.
00:24
So here we have sb2, s3, reacting in air, which means with oxygen, to form sb2.
00:35
2 .03.
00:37
Okay? and then it says you reduce it with carbon in order to get the pure metal.
00:45
Additionally, if we look at set up bismuth down here, we have bi2s3 reacting in air to form bi2 .03 and then reducing it with carbon to produce just the metal.
01:04
Now you'll notice i have a few other things added here.
01:07
Okay.
01:09
So the reason i've included so2 being released is because this sulfur here is not accounted for in this next step.
01:24
Okay? so this sulfur is going to release in the form of so2 with oxygen.
01:31
Same in the case of bismuth down here.
01:34
So now we need to balance.
01:37
And so the best way to do this, is to simply start.
01:45
So let's start with sulfur.
01:51
Okay? so here, sulfur, there's three on the left, so we can make three on the right.
01:59
However, now on the right, if we load to get oxygen, there's three, six, seven, eight, nine.
02:05
So now there's nine oxygen over here, and over here there's only two.
02:11
So since nine isn't divisible by two, we have to have nine halves.
02:17
Now, a lot of times this isn't acceptable.
02:21
So what we're going to do is multiply all of our coefficients by two to get rid of this.
02:28
Okay.
02:30
So here we go.
02:32
This will be two.
02:34
If we multiply this by two, we get nine.
02:41
Okay.
02:42
This will then produce six.
02:47
Okay.
02:48
And then this will be two.
02:49
So let's double check that.
02:53
Oxygen would be a good first place.
02:54
So oxygen, we have 18.
02:58
And over here we have 612 plus 6, 18.
03:04
So 18 oxygen, 18 oxygen.
03:06
Good.
03:08
Now let's check our antimony.
03:10
Make sure those add up...