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Write balanced equations and solubility product expressions for the solubility equilibria of the following compounds: (a) $\mathrm{CuBr},$ (b) $\mathrm{ZnC}_{2} \mathrm{O}_{4},(\mathrm{c}) \mathrm{Ag}_{2} \mathrm{CrO}_{4}$ (d) $\mathrm{Hg}_{2} \mathrm{Cl}_{2},(\mathrm{c}) \mathrm{AuCl}_{3},(\mathrm{f}) \mathrm{Mn}_{3}\left(\mathrm{PO}_{4}\right)_{2}$.

a) $K_{s p}=\left[C u^{+}\right] \cdot\left[B r^{-}\right]$b) $K_{s p}=\left[Z n^{2+}\right] \cdot\left[C O_{2}^{2-}\right]$c) $K_{s p}=\left[A g^{+}\right]^{2} \cdot\left[C r O_{4}^{2-}\right]$d) $K_{s p}=\left[H g^{+}\right]^{2} \cdot\left[C l^{-}\right]^{2}$e) $K_{s p}=\left[A u^{3+}\right] \cdot\left[C l^{-}\right]^{3}$f) $K_{s p}=\left[M n^{2+}\right]^{3} \cdot\left[P O_{4}^{3-}\right]^{2}$

Chemistry 102

Chapter 16

Acid-Base Equilibria and Solubility Equilibria

Acid-Base Equilibria

Aqueous Equilibria

University of Maryland - University College

University of Kentucky

Brown University

Lectures

00:41

In chemistry, an ion is an atom or molecule that has a non-zero net electric charge. The name was coined by John Dalton for ions in 1808, and later expanded to include molecules in 1834.

24:14

In chemistry, a buffer is a solution that resists changes in pH. Buffers are used to maintain a stable pH in a solution. Buffers are solutions of a weak acid and its conjugate base or a weak base and its conjugate acid, usually in the form of a salt of the conjugate base or acid. Buffers have the property that a small change in the amount of strong acid or strong base added to them results in a much larger change in pH. The resistance of a buffer solution to pH change is due to the fact that the process of adding acid or base to the solution is slow compared to the rate at which the pH changes. In addition to this buffering action, the inclusion of the conjugate base or acid also slows the process of pH change by the mechanism of the Henderson–Hasselbalch equation. Buffers are most commonly found in aqueous solutions.

02:29

Write balanced equations a…

02:15

Write solubility product e…

02:11

01:42

Write the solubility produ…

00:58

02:35

Write balanced equations…

04:57

01:21

Hello. So today we'll be looking at different compounds and writing there. Caspi expressions. So first, let's look a copper, bro. Mean, So we're going to take copper romaine, and we're going to put it in water, which will make it. This is partially due associate. Now we're going to find what ions are going to be in here. So we know bro. Mean is a halogen, and Hala Jin's can gain one electron to have a full balance. So Hella Jin's, I doubt you will ever see it in any other form than, ah, in a negative one eye on. So we're gonna have a negative one. Ah, quiz, Rhone mean. And we want this to be balanced. So that means that copper's also have a positive one charge. So the borough mean that's a minus one and coppers a plus one. And so, if you draw the Kate, read the kiss, be expression you will see that will be copper plus and the coefficient will be one. Since there's only one and there will be times, bro. Mean minus. Now, let's take a look at zinc obsolete. So we're gonna take Zinc Oxley and we're going to put it. Water is going to partially disassociate. Now, what kind of ions would it make? Well, we've got this Aqsa late and hopefully you should know Aqsa late as a negative to charge. And now zinc. It was a transition metal. If we want it, the overall charge to be neutral because, you know, it's ah ionic solids. So if the oxide has a to minus charges, Inc must have a two plus charge. And now we see that a dissociated everything is in a 1 to 1 ratio. So the chaos p would just be the zinc two plus ion concentration times the Aqsa Late concentration. Now let's look at this Silver Crow, mate. You. So we're going to take the Silver Crow, mate. We're gonna put it in water, and it's going to form two Silver High owns and crummy I own. So hopefully you should know that Comey has a to minus charge and we have two silvers. So if you want the church to a balanced, we go positive. One charge toe, silver and silver usually has a positive one charge. They're two of them. Everything will expel inst and so the Casspi we're gonna have the concentration of the silver and the coefficient in front of the silver is the too. So that means we're gonna put it to the to power and then crawl up. Mate has only a one in front of it, which is kind of invisible. So we're gonna leave. Ah, because sort of invisible one power There. Now, let's look at this. So we're gonna take this mercury chloride, We're going to put it in water, and you should probably realize really quickly chlorine as a halogen. So it will form a negative one. I on there, two coins. So we're gonna put it like that. Mercury conform to Ohioans. In this case, if we have to Corinne's with a negative one charge. We need toe balance, that what then we want. And we have to Mercury's and they're gonna have a positive one charge. And if you're curious, other eye on that mercury conform is this one right here, right to Mercury's air connected. And there's a positive one charge. But that wasn't the case here. So let's draw the Casspi. So the mercury concentration Mercuri one plus and there's a two in front of it. So we have it to the second power. Then the coin, they get a one and I on and there it's also to in front of it. So we're gonna put it to the second power. Now, look, look. Its let's look at gold quarried. So we've got gold chloride. We're gonna put it in water, and it's gonna associate the first thing you should notices. Coin is a halogen, which means it will have a negative one charge because no, it just wants to gain one electron there. Three of, um So there has to be three of these and ions. Now there's only one gold, and this is each Chlorine has a negative one charge in there, three of them, So gold needs to have a three plus charge. Now let's write the Casspi. So concentration of the gold times the concentration of the chlorine and it's chloride ion, and it's gonna be to the third power cause there's a three coefficient in front of it. Now let's look at Mangga knees phosphate. So gonna take manganese phosphate and we're gonna put it in water. And hopefully you should recognize past fate, which is ah three minus ion. And there are two of them. So that s so That's a total of negative six charge. So we need a positive six charge from the manganese. So there are three of them. Six divided by three is a two plus charge. So so the case p of this, I would simply be the man. Guineas two plus concentration to the third power cause it has a three coach efficient in front of it and then terms the phosphate concentration, and it's to the second power cause has a two coefficient in front of it.

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