Question

Write balanced equations for the following reactions: (a) the heating of aluminum carbonate; (b) the reaction between $\mathrm{AlCl}_3$ and K ; (c) the reaction between solutions of $\mathrm{Na}_2 \mathrm{CO}_3$ and $\mathrm{Ca}(\mathrm{OH})_2$.

   Write balanced equations for the following reactions: (a) the heating of aluminum carbonate; (b) the reaction between $\mathrm{AlCl}_3$ and K ; (c) the reaction between solutions of $\mathrm{Na}_2 \mathrm{CO}_3$ and $\mathrm{Ca}(\mathrm{OH})_2$.
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Chemistry
Chemistry
Raymond Chang, Jason… 14th Edition
Chapter 21, Problem 63 ↓
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Write balanced equations for the following reactions: (a) the heating of aluminum carbonate; (b) the reaction between $\mathrm{AlCl}_3$ and K ; (c) the reaction between solutions of $\mathrm{Na}_2 \mathrm{CO}_3$ and $\mathrm{Ca}(\mathrm{OH})_2$.
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NCERT Class 10 Science


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Transcript

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00:01 Okay, this is question 68 from chapter 23 and they give us three reactions to balance.
00:08 Okay, so a is asking the balance an aluminum carbonate, so a .o2, co3, with heat.
00:26 So what happens when it's heated? this produces an aluminum oxide plus carbon dioxide.
00:51 Okay, but we're not done.
00:52 Yet because we actually have to balance the reactions as you see the aluminum's a balance but the carbons and oxygens there's a lot more on the reactant side of the product side to the fixed it was going to add a three the carbon dioxide and now there's three carbons on both sides and nine octaves okay for b we have aluminum chloride plus potassium and this is going to react to make all we do is just switch the potassium and aluminum side so you have kco with aluminum by itself okay so and now for this as you can see we have three chlorides on that side and one quora on that side so we want to try to balance i'm going to put a three in front of the potassium chloride but now there's three potassium on this side and this side and one chloride and we're going to try to balance i'm going to put a three in front of the potassium chloride but now there's three potassium on this side and and one on that side, so we add a 3 in front of 2...
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