00:01
Let's write the balance in the ionic equation.
00:03
So the following in basic solution.
00:07
For a unbalanced, i'm going to break this apart into two separate half reactions.
00:34
Put a two here to balance the sulfur.
00:39
Six oxygen on each side.
00:41
Minus four in the left.
00:43
Two electrons to give us minus four on the right, and that's balanced.
00:47
Second half reaction.
00:55
Two to balance the iodine.
00:58
Two electrons to balance to charge.
01:00
Electrons will cancel and this together.
01:17
And there's our balanced reaction.
01:21
And this one is neither acidic or basic solutions.
01:24
We don't need to do anything extra.
01:28
For b, we have mn2 plus h2o2 to mno2 and h2 break apart into two half reactions.
01:47
We'll have mn2 plus.
01:48
To mno2 solid.
01:58
Manganese is balanced.
02:00
Two oxygen on the right, so 2h2o on the left.
02:05
Balance the hydrogen by 4h plus on the right.
02:08
Balancing the charge by two electrons on the right.
02:13
Second half reaction, balance the oxygen, balance the hydrogen, balance the electrons, two electrons on each side.
02:32
Cancel 2h2 on each side cancel 2h plus will leave me with 2h plus on the right and i'm left with mn2 plus add h202 to mn02 add 2h plus we're going to switch this into basic solution now will yield 2h plus and 2 .0h minus to 2h2o.
03:23
2h plus and i'm left with mn2 plus, add h202, add 2oh minus to mno2 solid, and 2h2.
03:43
And there's our balanced equation in basic solution.
03:52
C we have zinc solid and no3 minus aqueous to nh3 and znoh 4 to minus aqueous.
04:11
Break this up into two half reactions.
04:14
We'll have zinc solid to zinc oh four two minus aqueous.
04:22
Zinc is balanced on each side.
04:25
Four oxygen's on the right.
04:26
So 4h2o on the left, 8 hydrogens on the left.
04:35
I have 4, so another 4 on the right.
04:39
And the charge, only 2 electrons on the right to balance the charge.
04:46
N .03 minus to nh3, nitrogen, one on each side.
04:54
Three oxygens on the left, so 3h2o on the right.
04:59
Nine hydrogens on the right, so nine hydrogens on the left.
05:05
And to balance the charge, i need eight electrons on the left.
05:13
Cancel it the electrons, we'll multiply the first half reaction by four, the second half reaction by one, to get eight electrons as a common multiple...