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(a) For $\mathrm{KrF}_{4}$:
- Krypton (Kr) has 8 valence electrons.
- Each Fluorine (F) has 7 valence electrons, and there are 4 Fluorines: $4 \times 7 = 28$.
- Total = $8 + 28 = 36$ valence electrons.
(b) For $\mathrm{ClO}_{3}^{-}$:
- Chlorine (Cl) has 7
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