Question
Write each equation in slope-intercept form. Without graphing the equations, state whether the system of equations has exactly one solution, no solution, or an infinite number of solutions. $\frac{x}{3}+\frac{y}{4}=1$$4 x+3 y=12$
Step 1
For the first equation, $\frac{x}{3}+\frac{y}{4}=1$, we can solve for $y$ as follows: $\frac{y}{4} = 1 - \frac{x}{3}$ $y = 4\left(1 - \frac{x}{3}\right)$ $y = 4 - \frac{4x}{3}$ So the first equation in slope-intercept form is $y = -\frac{4}{3}x + 4$. For the Show more…
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