For the first equation, $\frac{x}{3}+\frac{y}{4}=1$, we can solve for $y$ as follows:
$\frac{y}{4} = 1 - \frac{x}{3}$
$y = 4\left(1 - \frac{x}{3}\right)$
$y = 4 - \frac{4x}{3}$
So, the first equation in slope-intercept form is $y = -\frac{4}{3}x + 4$.
For
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