For the first equation, $\frac{x}{3}+\frac{y}{4}=1$, we can solve for $y$ as follows:
$\frac{y}{4} = 1 - \frac{x}{3}$
Multiply both sides by 4 to get rid of the fraction:
$y = 4(1 - \frac{x}{3})$
Now, distribute the 4:
$y = 4 - \frac{4x}{3}$
So, the first
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