Question
Write each solution set in interval notation.$$x^{2}(x+4)^{2} \geq 0$$
Step 1
The zeros occur when $x = 0$ and when $x = -4$. This is because if we substitute $x = 0$ into the inequality, we get $0^2 \times (0+4)^2 = 0$. Similarly, if we substitute $x = -4$, we get $(-4)^2 \times (-4+4)^2 = 0$. Show more…
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